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yKpoI14uk [10]
3 years ago
7

How can you maintain a balance between high-risk and low-risk investments?

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0
<h2>Answer:</h2>

<u>We can maintain a balance by </u><u>varying the investments</u>

<h2>Step-by-step explanation:</h2>

The balance between high risk and low risk investment can be maintained by keeping the investment diversifying or varied. When we diversify our investments we get the highest potential return for a low amount of risk. Investing in only a handful of stocks is risky because if the price is fluctuated then it can affect the whole investment.

Nesterboy [21]3 years ago
5 0
Diversifying your investment will help you maintain a balance between high-risk and low-risk investments.
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1,9,4,6,8,8 which is the median
vladimir1956 [14]
<h3>Answer:  Median = 7</h3>

=======================================================

Explanation:

Sort the values from smallest to largest. Doing so leads to the list {1,4,6,8,8,9}

Since the set is small enough, you can probably notice that the middle most number is a tie between the 6 and the first 8. The midpoint is (6+8)/2 = 14/2 = 7.

The median is 7.

---------------

If you wanted, you could cross off the first and last items of the set

That means we go from {1,4,6,8,8,9} to {4,6,8,8}

Then repeat to get the smaller set {6,8}

This shows we have a tie between the 6 and 8 as the middle most item, and why 7 is the median (since 7 is the midpoint between 6 and 8).

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3 years ago
A function is represented by the values in the table.
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Answer:

IS LINEAR

Step-by-step explanation:

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3 years ago
Which line segment is a diameter of circle L?
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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
vfiekz [6]
For AD:
 AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
 For BC:
 
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
 For AB:
 
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
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8 0
3 years ago
6x-5y=15 x=y+3 find x and y
arlik [135]

Answer:

(0, -3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

6x - 5y = 15

x = y + 3

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                                                                                                  6(y + 3) - 5y = 15
  2. Distribute 6:                                                                                                    6y + 18 - 5y = 15
  3. Combine like terms:                                                                                        y + 18 = 15
  4. [Subtraction Property of Equality] Subtract 18 on both sides:                     y = -3

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x = y + 3
  2. Substitute in <em>y</em>:                                                                                                   x = -3 + 3
  3. Add:                                                                                                                   x = 0
7 0
3 years ago
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