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3 years ago

7

How can you maintain a balance between high-risk and low-risk investments?

2 answers:

Pani-rosa [81]3 years ago

7 0

<h2>Answer:</h2>

<u>We can maintain a balance by </u><u>varying the investments</u>

<h2>Step-by-step explanation:</h2>

The balance between high risk and low risk investment can be maintained by keeping the investment diversifying or varied. When we diversify our investments we get the highest potential return for a low amount of risk. Investing in only a handful of stocks is risky because if the price is fluctuated then it can affect the whole investment.

Nesterboy [21]3 years ago

5 0

Diversifying your investment will help you maintain a balance between high-risk and low-risk investments.

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David buys a new racing bike for £x he then sells it for £1584 making a loss of 12% find x

Sholpan [36]

Answer:

x=1800

Step-by-step explanation:

x-1584/x=0.12

x-1584=0.12x

x-0.12x=1584

0.88x=1584

x=1800

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2 years ago

y=−2x+4 Complete the missing value in the solution to the equation. ( −2) Need it quick no explanation need.

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2 years ago

I'LL GIVE YOU BRAINIEST!<br> 1 1/5 · x/3 = 9/10 solve for x

joja [24]

$\huge\text{Hey there!}$

$\huge\textbf{Equation:}$

$\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\huge\textbf{Solve:}$

$\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\huge\textbf{Simplify it:}$

$\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}$

$\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}$

$\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}$

$\huge\textbf{Simplify it:}$

$\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}$

$\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}$

$\mathbf{\rightarrow x = \dfrac{45}{20}}$

$\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}$

$\mathbf{\rightarrow x = \dfrac{9}{4}}$

$\mathbf{x \approx 2 \dfrac{1}{4}}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

2 years ago

Read 2 more answers

Identify the initial value and rate of change for the graph shown

Juliette [100K]

I'm going to have to say C.

8 0

3 years ago

Read 2 more answers

Please help! will friend! and branliest!

Akimi4 [234]

Answer:

Option A, no trend

Step-by-step explanation:

<u>Since the points are all over the graph, that means that there is no trend.</u>

<u />

If all the points followed a straight line toward positive infinity, it would be positive trend.

If all the points followed a straight line toward negative infinity, it would be negative trend.

Answer: Option A, no trend

7 0

3 years ago