Question

Which number can each term of the equation be multiplied by to eliminate the fractions before solving? 6 – x + = 6 minus StartFraction 3 Over 4 EndFraction x plus StartFraction 1 Over 3 EndFraction equals StartFraction one-half EndFraction x plus 5.x + 5 2 3 6 12

Answer 1

Answer:

12

Explanation:

i dont know hahaha but its 12 i cheat hahaha

Answer 2

Answer:

We need to multiply 12 to each term to eliminate fractions.

Explanation:

Given expression:

$6-\frac{3}{4}x+\frac{1}{3}=\frac{1}{2}x+5$

To eliminate the fraction we need to multiply each term by least common multiple of the denominators of the fraction.

The denominators in the above expressions are:

4, 3 and 2

The multiples of each can be listed below.

2⇒ 2,4,6,8,10,12,14,16.....

3⇒ 3,6,9,12,15,18

4⇒ 4,8,12.......

From the list of the multiples stated, we can see the least common multiple is 12.

So we will multiply each term by 12.

Multiplying 12 to both sides.

$12(6-\frac{3}{4}x+\frac{1}{3})=12(\frac{1}{2}x+5)$

Using distribution,

$72-9x+4=6x+60$

Thus we successfully eliminated the fractions.