a car travelling at 50m/h on a horizontal highway (a) if the coefficient of static friction between road and tyres on a rainy da
y is 0.100, what is the minimum distance in which the car will stop?
1 answer:
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Answer:
c. 981 watts
Explanation:
Given:
- horizontal speed of treadmill,
- weight carried,
- grade of the treadmill,
<u>Now the power can be given by:</u>
(where grade is the rise of the front edge per 100 m of the horizontal length)
Answer:
15.6m/s
Explanation:
V1= because the derivate of the position is the velocity
V1=12t+3
V2=20+-8t because the integral of the acceleration is the velocity
V2=
V1=V2 to see when the velocities of particles match
12t+3=20-4t^2
4t^2+12t-17=0 we resolve this with
and we take the positif root
t=1.05 sec
if we evaluate the velocity (V1 or V2) the result is 15.6m/s