a car travelling at 50m/h on a horizontal highway (a) if the coefficient of static friction between road and tyres on a rainy da
y is 0.100, what is the minimum distance in which the car will stop?
1 answer:
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Answer:
39.7 m
Explanation:
First, we conside only the last second of fall of the body. We can apply the following suvat equation:
where, taking downward as positive direction:
s = 23 m is the displacement of the body
t = 1 s is the time interval considered
is the acceleration
u is the velocity of the body at the beginning of that second
Solving for u, we find:
Now we can call this velocity that we found v,
v = 18 m/s
And we can now consider the first part of the fall, where we can apply the following suvat equation:
where
v = 18 m/s
u = 0 (the body falls from rest)
s' is the displacement of the body before the last second
Solving for s',
Therefore, the total heigth of the building is the sum of s and s':
h = s + s' = 23 m + 16.7 m = 39.7 m
The heat energy required is 2983 J
Explanation:
When an amount of energy Q is supplied to a certain sample of substance of mass m, the temperature of the substance increases by an amount of according to the equation
:
where
Q is the heat supplied
m is the mass of the object
is the specific heat capacity of the substance
is the change in temperature
For the glass bottle in this problem:
is the change in temperature
is the specific heat of glass
Substituting into the equation, we find
Learn more about specific heat capacity:
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