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1 year ago

How do you find the missing terms in a number sentence?

1 answer:

5 0

Determine the rule that the numbers in the sequence obey, and then utilize this rule to determine the missing term to complete a number sequence. The rule that the numbers in the example above adhere to is "Add 8 and then remove 2." Therefore, 32 is the term that is missing from the given number sequence.

<h3>What is a number sentence?</h3>

A number sentence is an equation or inequality that is articulated using numbers and mathematical symbols in the context of mathematics education.
In the US, Canada, UK, Australia, New Zealand, South Africa, and other countries, the phrase is used in the instruction of elementary-level mathematics.
The word is employed when asking pupils to write equations using fundamental mathematical symbols.
Unknown values are sometimes denoted by boxes or forms.
To introduce pupils to the ideas of structure and basic algebra before more formal teaching of these concepts, number sentences are utilized.

<h3>A math sentence is what?</h3>

A mathematical statement about two expressions is made.
Either integers, variables, or a combination of both are used in the two phrases.
Additionally, words or symbols like equals, greater than, or less than can be used in a mathematical phrase.

Learn more about number sentences here:

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What is the velocity of a proton that has been accelerated by a potential difference of 15 kV? (i)\:\:\:\:\:9.5\:\times\:10^5\:m

andre [41]

Answer:

Velocity of a proton, $v=1.7\times 10^6\ m/s$

Explanation:

It is given that,

Potential difference, $V=15\ kV=15\times 10^3\ V$

Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.

Using the conservation of energy as :

$\dfrac{1}{2}mv^2=qV$

q is the charge of proton

m is the mass of proton

$v=\sqrt{\dfrac{2qV}{m}}$

$v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 15\times 10^3\ V}{1.67\times 10^{-27}\ kg}$

$v=1695361.75\ m/s$

$v=1.69\times 10^6\ m/s$

$v=1.7\times 10^6\ m/s$

So, the velocity of a proton is $1.7\times 10^6\ m/s$ . Hence, this is the required solution.

8 0

4 years ago

When you park your car uphill next to a curb, the right front wheel should be:?

Cloud [144]

<span> When headed uphill at a </span>curb<span>, turn the front </span>wheels<span> away from the </span>curb<span> and let </span>your vehicle<span> roll backwards slowly until the rear part of the front </span>wheel<span> rests against the </span>curb<span> using it as a block.</span>

6 0

3 years ago

How does the government shape technology?

Marat540 [252]

Answer:

Society is a group of people that share similar values and beliefs.

The development of technology is affected by society and its changing values, politics, and economics

Explanation:

8 0

3 years ago

What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?

Brilliant_brown [7]

Answer:

The acceleration of the proton is 9.353 x 10⁸ m/s²

Explanation:

Given;

speed of the proton, u = 6.5 m/s

magnetic field strength, B = 1.5 T

The force of the proton is given by;

F = ma = qvB(sin90°)

ma = qvB

where;

m is mass of the proton, = 1.67 x 10⁻²⁷ kg

charge of the proton, q = 1.602 x 10⁻¹⁹ C

The acceleration of the proton is given by;

$a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2$

Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²

4 0

3 years ago

The process of changing the energy of a system by means of force. Force * Diatance

Dmitry_Shevchenko [17]

This is known as work

7 0

3 years ago