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3 years ago

Help will give 20 points!

Mathematics

2 answers:

podryga [215]3 years ago

6 0

Answer: What do you need help with?

Step-by-step explanation: I can help with anything.

kvasek [131]3 years ago

6 0

Answer:

help with what i don't see a picture

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How to solve equation by factoring 3x^2+16x-44=0

Alexxx [7]

The answer is x=1.76 or 2

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3 years ago

Two lines are represented by the equations -1/2y=6x+10 and y=mx for which value of m will the lines be parallel

hjlf

Answer:

-12

Step-by-step explanation:

So to start we need to know what makes a line parallel. In an equation we know that for lines to be parallel they must have the same slope(m).

Then, we need to know the slope-intercept form of an equation. The slope intercept form is $y=mx+b$ where $m$ is the slope of the line and $b$ is the y-intercept. In this problem where can see the second equation is already in this form.

Now that we know we need to find the slope, and we know that the second equation is in slope-intercept form we're going to convert the fist equation into the correct form.

To do this, we know we need to make sure $y$ is the only thing on the left side of the equal sign. Currently, on the left side of the equal sign we have $-\frac{1}{2} y$ so we have to divide both sides by $-\frac{1}{2}$ to get $y=-12x -20$

Now that we have it converted to slope-intercept form, we are going to look for what represents the slope or $m$ in the equation. In this case the slope would be -12, so any line with a slope of -12 will be parallel.

8 0

3 years ago

Determine if f(x)= x + 12/ x is even, odd, or neither

Reptile [31]

F(-x)=-x+(12/-x)=-x-12/x
odd function

3 0

3 years ago

Latasha is a waitress at Seventh Heaven Hamburgers. She wants to estimate the mean amount each group at a table leaves for a tip

elena55 [62]

Forgive me if this is wrong. I haven't done stat in a year, but comment if you need clarification!

3 0

3 years ago

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago