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3 years ago

15

Can someone help me?

1 answer:

Ann [662]3 years ago

7 0

Answer:4/3

Step-by-step explanation:

2/6=x/4 cross multiply

6x=8 x=8/6 =4/3 Divide and simplify

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What is the factored form of b3 − 1,000?

DochEvi [55]

Kindly, check the attachment below to see the answer.

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3 years ago

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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the plate, including t

vredina [299]

You're looking for the extreme values of $x^2+3y^2+13x$ subject to the constraint $x^2+y^2\le1$ .

The target function has partial derivatives (set equal to 0)

$\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2$

$\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0$

so there is only one critical point at $\left(-\dfrac{13}2,0\right)$ . But this point does not fall in the region $x^2+y^2\le1$ . There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of $x^2+y^2\le1$ by

$x=\cos u$

$y=\sin u$

with $0\le u$ . Then $t(x,y)$ can be considered a function of $u$ alone:

$t(x,y)=t(\cos u,\sin u)=T(u)$

$T(u)=\cos^2u+3\sin^2u+13\cos u$

$T(u)=3+13\cos u-2\cos^2u$

$T(u)$ has critical points where $T'(u)=0$ :

$T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0$

$(1)\quad\sin u=0\implies u=0,u=\pi$

$(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4$

but $|\cos u|\le1$ for all $u$ , so this case yields nothing important.

At these critical points, we have temperatures of

$T(0)=14$

$T(\pi)=-12$

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0

3 years ago

PLZ, help me with this question.

Korolek [52]

Answer:

Intensity

Step-by-step explanation:

In physics, intensity of radiant energy is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy.

8 0

3 years ago

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I need your help guys !!!!!!!!

Ber [7]

$\bold{\huge{\blue{\underline{ Solution}}}}$

$\bold{\underline{ We \: have \:given \: that, }}$

<u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
<u>The </u><u>height </u><u>of </u><u>the </u><u>tower </u><u>is </u><u>6</u><u>0</u><u> </u><u>m </u>
<u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>

$\bold{\underline{ Now}}$

<u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>

$\bold{\underline{ So, }}$

$\sf{ CE = 25m }$

<u>Therefore</u><u>, </u>

$\sf{ AB = AD - CE }$

$\sf{ AB = 60 - 25 }$

$\sf{ AB = 35 m }$

<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>

$\bold{tan Φ =}{\bold{\frac{ AB}{BC}}}$

$\bold{tan Φ =}{\bold{\frac{ 35}{35}}}$

$\bold{ tan Φ = 1 }$

$\bold{ tan Φ = 45 °}$

$\sf{\red{Hence, \: The \:angle \:of \:depression\: is \:45°}}$

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2 years ago

SSC's Tuatara is the fastest car in the world with 331 miles per hour

Kipish [7]

Answer:

5.517miles/min

Step-by-step explanation:

331/1h

=331/(1*60) because 1h=60min

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3 years ago