Which phases do not always fill their containers? Select all that apply

One fragment of a given integer n can be selected and its digits reversed (replaced with a right to left version of themselves).

andrew11 [14]

Integers are numbers without decimal points. The number could be positive, negative or zero

<h3>How to determine the maximum number from the integer</h3>

The maximum number from integer N can be determined using the following program written in Python, where comments are used to explain each line

#This prompts the user for input

num = input("Number: ")

#This iterates from 0 to 9

kount = [0 for x in range(10)]

# This iterates through the input, and updates the kount variable

for i in range(len(num)):

kount[int(num[i])] = kount[int(num[i])] + 1

# This next two lines initialize the greatest number

greatestNum = 0

multiplier = 1

# This iterates through the kount array

for i in range(10):

#The following is repeated while the current element is greater than 0

while kount[i] > 0:

#This generates the greatest number

greatestNum = greatestNum + ( i * multiplier )

kount[i] = kount[i] - 1

multiplier = multiplier * 10

#This prints the greatest number

print(greatestNum)

Read more about similar programs at:

brainly.com/question/26426553

7 0

2 years ago

Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca

antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

$T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t}$ (1)

Where:

$T_{s}$ - Final temperature, in degrees Celsius.
$T_{o}$ - Initial temperature, in degrees Celsius.
$t$ - Time, in minutes.
$k$ - Cooling rate, in $\frac{1}{min}$ .
$T(t)$ - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when $T(t) = T_{s}$ , that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that $T_{o} = 80\,^{\circ}C$ , $t = 15\,min$ , $T_{s} = 50\,^{\circ}C$ and $T(15) = 60\,^{\circ}C$ , then the cooling rate of the substance is: