Fermat's little theorem states that
≡a mod p
If we divide both sides by a, then
≡1 mod p
=>
≡1 mod 17
≡1 mod 17
Rewrite
mod 17 as
mod 17
and apply Fermat's little theorem
mod 17
=>
mod 17
So we conclude that
≡1 mod 17
Answer:
JL = 78
Step-by-step explanation:
MN is a midsegment. Based on the midsegment theorem,
MN = ½(JL)
MN = 5x - 16
JL = 4x + 34
Plug in the value
5x - 16 = ½(4x + 34)
5x - 16 = ½*4x + ½*34
5x - 16 = 2x + 17
Collect like terms
5x - 2x = 16 + 17
3x = 33
Divide both sides by 3
x = 11
✔️JL = 4x + 34
Plug in the value of x
JL = 4(11) + 34
JL = 44 + 34
JL = 78
Answer:
1/25 k^2
Step-by-step explanation:
Answer:
it is C the 4
Step-by-step explanation:
-6 to pos 4
Answer:
Step-by-step explanation:
sin(2x) = 2 sin(x) cos(x) cos(2x) = cos2(x) – sin2(x) = 1 – 2 sin2(x) = 2 cos2(x) – 1. Now I am not sure if this is right but I remember another similar formula. Here is the correct formula cot x = cos x / sin x
2 ) ( sin² x + cos² x ) / cos x = sec x
1/cos x = sec x
sec x = sec x
cos² x + sin² x = 1
