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Tju [1.3M]
3 years ago
5

Wats the simplest form of 1.125

Mathematics
2 answers:
Ghella [55]3 years ago
5 0
1.125 = 1125/1000 = 9/8
lys-0071 [83]3 years ago
3 0
<span>Step 1: 1.125 = 1 125⁄1000</span><span> </span>
<span>Step 2: Simplify 1 125⁄1000 = 1 1⁄8</span><span> </span>

<span>
</span>
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Plz I need help with this ASAP
Hoochie [10]
3x^2 / 4 = 48

Multiply both sides by 4 to get rid of the four on the left.

3x^2 = 192

Divide both sides by 3

x^2 = 64

The square root 64 to get x

Remember there are two answers

x = 8 and x = -8
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2 years ago
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Mr. mole left his burrow
pav-90 [236]

Answer:Did he ever come back?

Step-by-step explanation:

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3 years ago
You pick 5 digits (0-9) at random without replacement, and write them in the order picked. What is the probability that you have
Tanzania [10]

Answer:

Probability is : 1/30240= 0.000033068

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You pick 5 digits (0-9) at random without replacement, and write them in the order picked.

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4 0
3 years ago
One tool used in genetics is called a pedigree chart,are there any advantages to using this tool?The population of a city is inc
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Answer:

A = 236,000 (1.04)^t

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Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:  

A = P (1 + r) t  

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A = population after t years  

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4 0
3 years ago
If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
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