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tangare [24]
3 years ago
13

Which statement is true? A.Two angles can be complementary and equal. B.Two angles cannot be equal if they are complementary. C.

An angle can be complementary only if it is 90°. D. Only three angles can be supplementary.
Mathematics
1 answer:
o-na [289]3 years ago
3 0
A because complementary angles means 2 angles that add together to equal 90 degrees and it's possible for both angles to be 45.
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Simplify these expressions
Xelga [282]
\frac{10a}{2} \\ \\ 5a \\ \\

The answer is: 5a

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\frac{36b}{6b} \\ \\  \frac{36}{6} \\ \\ 6 \\ \\

The answer is: 6

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\frac{16c^2}{8c} \\ \\ 2c^{2-1} \\ \\ 2c^1 \\ \\ 2c \\ \\

The answer is: 2c

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\frac{18ab^2}{2b} \\ \\ 9ab^{2-1} \\ \\ 9ab^1 \\ \\ 9ab \\ \\

The answer is: 9ab

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\frac{40b^2c^2}{5bc} \\ \\ 8b^{2-1} c^{2-1} \\ \\ 8b^1c^1 \\ \\ 8bc^1 \\ \\ 8bc \\ \\

The answer is: 8bc

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\frac{63ab^2c^3}{7b^2c^2} \\ \\  \frac{63ac^3}{7c^2} \\ \\ 9ac^{3-2} \\ \\ 9ac^1 \\ \\ 9ac \\ \\

The answer is: 9ac
6 0
3 years ago
Four subtracted from twice a number is two. what is the number
EastWind [94]

Answer: 3

Step-by-step explanation:

      First, we will write a mathematical equation for the phrase given.

-> Let n be "a number"

             four subtracted from twice a number is two

             four subtracted from twice a number = 2

             (twice a number) - 4 = 2

             2n - 4 = 2

      Now, we will solve this equation by isolating the variable.

             2n - 4 = 2

             2n = 6

             n = 3

<em>Read more about </em><em>algebraic equations </em><em>here:</em>

<em>brainly.com/question/27791850</em>

8 0
2 years ago
C(2, 5), D(3, 1)<br><br> Find the slope of the line that passes through each pair of points.
Tpy6a [65]
Slope=-4 or -4/1

Work:

(2, 5) (3, 1)
x1 y1. x2 y2

M= y2-y1/x2-x1
M= 1-5/3-2
M= -4/1
M=-4
5 0
3 years ago
Dolores bought 3 tapes that cost $4.95 each. the tax on her purchase was %6. What was her total bill​
SpyIntel [72]

Answer:15.741

Step-by-step explanation: 4.95*3= 14.85, 14.85* 0.06= 0.891+14.85=15.741

Hope it helped!

7 0
3 years ago
A piece of wire 11 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
forsale [732]

Answer:

11 meters

Step-by-step explanation:

First, we can say that the square has a side length of x. The perimeter of the square is 4x, and that is how much wire goes into the square. To maximize the area, we should use all the wire possible, so the remaining wire goes into the triangle, or (11-4x).

The area of the square is x², and the area of an equilateral triangle with side length a is (√3/4)a². Next, 11-4x is equal to the perimeter of the triangle, and since it is equilateral, each side has (11-4x)/3 length. Plugging that in for a, we get the area of the equilateral triangle is

(√3/4)((11-4x)/3)²

= (√3/4)(11/3 - 4x/3)²

= (√3/4)(121/9  - 88x/9 + 16x²/9)

= (16√3/36)x² - (88√3/36)x + (121√3/36)

The total area is then

(16√3/36)x² - (88√3/36)x + (121√3/36) + x²

= (16√3/36 + 1)x² -  (88√3/36)x + (121√3/36)

Because the coefficient for x² is positive, the parabola would open up and the derivative of the parabola would be the local minimum. Therefore, to find the maximum area, we need to go to the absolute minimum/maximum points of x (x=0 or x=2.75)

When x=0, each side of the triangle is 11/3 meters long and its area is

(√3/4)a² ≈ 5.82

When x=2.75, each side of the square is 2.75 meters long and its area is

2.75² = 7.5625

Therefore, a maximum is reached when x=2.75, or the wire used for the square is 2.75 * 4 = 11 meters

3 0
3 years ago
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