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3 years ago

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Algebra help please

1 answer:

Norma-Jean [14]3 years ago

6 0

-12,-11,-10,-9,-8,-7,-6,-5,-4 is the answer kid

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Ben is 12 years older than Ishaan. Ben and Ishaan first met two years ago. Three years ago, Ben was 4 times as old as Ishaan?

Marina86 [1]

The first statement means:

b=i+12,

The third statement means:

b-3=4(i-3),

b-3=4i-12

b=4i-9

Using the value for b from the first statement in the third statement gives you:

i+12=4i-9

-3i=-21

i=7: and since b=i+12

b=19

So Ben is 19 and Ishaan is 7.

6 0

3 years ago

Write the following<br> as an<br> algebraic expression.<br> Subtract 3x + 6 from 8x -1.

Katen [24]

Answer:

(8x - 1) - (3x + 6)

hope this helps

6 0

3 years ago

How much fencing is required to enclose a circular garden whose radius is 14 m? Use 3.14 pi

ipn [44]

Answer:

87.92 m

Step-by-step explanation:

Formula for the circumference of a circle (which is what you're finding with this problem) is pi d

Pi being 3.14 and d being the diameter

Since the radius is 14 the diameter is 2 times that , 28m

Now just multiply 28 and 3.14 which gives you 87.92

7 0

3 years ago

-3<br> 3m2n)<br> Which expression is equivalent to<br> ?<br> 6mn-2

andrezito [222]

Answer:

a

Step-by-step explanation:

8 0

3 years ago

The scores on a standardized exam are normally distributed with a mean of 400 and a standard deviation of 50.

S_A_V [24]

Using the normal distribution, it is found that approximately 40% of the scores are greater than 413.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, we have that the mean and the standard deviation of the scores are given by:

$\mu = 400, \sigma = 50$

Approximately 40% of the scores are greater than the 60th percentile, which is <u>X when Z = 0.253</u>.

Then:

$Z = \frac{X - \mu}{\sigma}$

$0.253 = \frac{X - 400}{50}$

X - 400 = 50(0.253)

X = 412.65.

Rounding up, approximately 40% of the scores are greater than 413.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

8 0

2 years ago