Answer:4, 6, 8,
Step-by-step explanation:
odd numbers 1,3,5,7,9,11
even numbers 2,4,6,8,10
Answer:
the answer is c: s=40(1.1)^m, s=20(1.15)^m
Step-by-step explanation:
in option A, (0.10) and (0.15) make it exponential decay rather than exponential growth like it's supposed to be.
In option B, the rate of growth is supposed to be on the exponent, not the sales themselves in the equation
option c is correct I just finished the test
option d has the same mistake as a and b combined
Answer:
40°, 60°, and 80°
Step-by-step explanation:
We know that the sum of the angles of a triangle is equal to 180°.
We can use this equation to solve for these angles:
180 = 2x + 3x + 4x
180 = 9x
20 = x
Then substitute the solution in for x to solve for the angles:
2(20) = 40°
3(20) = 60°
4(20) = 80°
Therefore, the angles are 40°, 60°, and 80°.
Answer:
The answer is below
Step-by-step explanation:
The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the answers to 3 decimal places.
(a) What is the probability that more than three aircraft arrive within an hour?
(b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals?
(c) Determine the length of an interval of time (in hours) such that the probability that no arrivals occur during the interval is 0.1.
Solution:
a) A poisson distribution is given by the formula:

λ = 1 hour
Therefore:
P(X > 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(x = 3)]




P(X > 3) = 1 - [0.3679+0.3679 + 0.1839 + 0.0613] = 0.019
b) Assuming 30 1 hour intervals, hence:
![P(X \leq 3)^{30}=[1-P(X\geq 30)]^{30}=(1-0.019)^{30}=0.5624](https://tex.z-dn.net/?f=P%28X%20%5Cleq%203%29%5E%7B30%7D%3D%5B1-P%28X%5Cgeq%2030%29%5D%5E%7B30%7D%3D%281-0.019%29%5E%7B30%7D%3D0.5624)
c) mean = 1 hour
mean = 1 / λ
1 = 1 / λ
λ = 1
The cumulative distribution function of a continuous variable is:


Answer:
Answer: 2x - 1
The x intercept is -1 and slope is 2
Branliest would be appreciated :)