Answer:
n < - 3 or n > - 2
Step-by-step explanation:
Inequalities of the type | x | > a , have solutions of the form
x < - a or x > a
Then
2n + 5 < - 1 or 2n + 5 > 1
Solve both inequalities
2n + 5 < - 1 ( subtract 5 from both sides )
2n < - 6 ( divide both sides by 2 )
n < - 3
OR
2n + 5 > 1 ( subtract 5 from both sides )
2n > - 4 ( divide both sides by 2 )
n > - 2
Solution is n < - 3 or n > - 2
For #2:
<span> 3x^2 + 4 – 2x^2 + 6</span>
<span><span>You need to combine your like terms:
</span>
3x^2 – 2x^2= x^2</span>
4 + 6 = 10
This will now give you:
<span>X^2 +10</span>
y/x = k
6.4/4 = 1.6
11.2 / 7 =1.6
16/10 = 1.6
20.8 /13 =1.6
This is a direct variation and the constant is 1.6
y=1.6x
