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Elanso [62]
3 years ago
5

Does the function f(x) = (0.85)\ represent exponential growth, decay, or neither?

Mathematics
1 answer:
Artemon [7]3 years ago
6 0
The function represents a linear relation so I assume the answer is B neither
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Given that KD is congruent to AT prove that angle K is congruent to angle T
Mademuasel [1]

KD is congruent to AT as:

<h3>angles are of equal measure</h3><h3>sides KD and TA are equal</h3><h3>sides DT and KA are equal</h3>

The figure is kite as has two pairs of same sides.

<h3>They are constructed in a way of having same angle.</h3>
7 0
2 years ago
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

8 0
3 years ago
Evaluate 11 to the 2nd power
lions [1.4K]

121)

11 times itself.

6 0
3 years ago
Using the given zero, find one other zero of f(x). i is a zero of f(x).= x4 - 2x3 + 38x2 - 2x + 37.
statuscvo [17]
If i is a zero, -i is also a zero.
The way you get a complex zero is by taking the square root of a negative number. Taking the sqrt (-1) = + and - i
4 0
3 years ago
Help&amp;EXPLAIN <br> •••••••••••••••••••
TiliK225 [7]

Answer:

68cm^2

Step-by-step explanation:

Well there's not much to explain - the problem statement does it for us.

The surface area is equal to the sum of areas of the walls. There's 2 l*w walls, 2 l*h walls and 2 h*w walls.

SA = 2*l*h + 2*l*w + 2*h*w

SA = 2*4cm*6cm + 2*4cm*1cm + 2*6cm*1cm = 48cm^2 + 8cm^2 + 12cm^2 = 68cm^2

5 0
3 years ago
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