The first thief takes (1/2 x + 1) . What remains ? x - (1/2x + 1)
So the 2nd thief takes 2/3 of [ x - (1/2x + 1) ]
What remains ? x - 2/3 [ x - (1/2x + 1) ]
So the 3rd thief takes 2/3 of { x - 2/3 [ x - (1/2x + 1) ] } and he takes 1 more .
What remains ? x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )
And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..
The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.
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This is a lot harder than just solving the problem with logic and
waving your hands in the air. Here's how you would do that:
Start from the end and work backwards:
-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.
Thank you for your generous 5 points.
B is the answer there is a common denominator y’a welcome
Answer:
m=9/8 or 1 1/8
Step-by-step explanation:
m= change in y over change in x
2 - -7 = 9
5 - -3 = 8
Answer:
5
Step-by-step explanation:
Pretty self-explanatory
By applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
<em>See the image in the attachment for the referred diagram.</em>
<em />
- The two triangles, triangle AEC and triangle BDC are similar triangles.
- Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.
<em>This implies that</em>:
<em><u>Given:</u></em>

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>
EC/DC = AE/DB



<u>b. </u><u>Find the length of </u><u>AB:</u>

AC = 6.15 cm
To find BC, use AC/BC = EC/DC.




Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
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brainly.com/question/14327552