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Brums [2.3K]
3 years ago
11

What is the different between 32bit anf 64 bit verision​

Computers and Technology
1 answer:
Elina [12.6K]3 years ago
8 0

<u>The different between 32 bit and 64 bit version:​</u>

  • The main difference between 32-bit and 64-bit versions is that a 32-bit version can access 2^3^2 memory addresses which is roughly equivalent to 4 GB of memory.
  • On the other hand, a 64-bit version can access 2^6^4 memory addresses which equates to a huge amount of memory, 16 exabytes to be precise.  
  • Nowadays, we observe that almost all the computers have 64-bit processors, which means that they can access any amount of memory over 4 GB till 16 exabytes.
  • 64-bit processors have various advantages like the increased speed of operations, smooth multitasking and they can also support video games and software's that have high graphical requirements.
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In a batch operating system, three jobs are submitted for execution. Each job involves an I/O activity, CPU time and another I/O
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Answer:

a) CPU utilization for uniprogramming system = 18.2%

b) CPU utilization for multiprogramming system = 41.379%

Explanation:

IO time = total time – CPU time

For JOB 1  

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total time= 23ms

IO time = 23-3 = 20ms ,

For JOB 2

CPU time =5ms

total = 29ms

IO time = 29-5 = 24ms  

For JOB 3  

CPU time = 4ms

total = 14ms

IO time = 14-10 =10ms  

1.) In uniprogramming system, operations are performed sequentially

CPU utilization=total CPU time / total real time

CPU utilization =(3+5+4) / (23+29+14)

CPU utilization =0.182 or 18.2%

2) In multiprogramming system, jobs wait for the CPU to get free while performing IO operations concurrently

steps followed by the os

1. IO for 1st job                           at 0ms

2. IO for 2nd job                          at 0ms

3. IO for 3rd job                          at 0ms

4. CPU time for 3rd job              at 5ms

5. Next IO job for 3rd job           at 9ms END at 14ms

6. CPU time for 1st job              at 9ms

7. Next IO job for 1st job           at 14ms END at 23ms

8. CPU time for 2nd job             at 14ms

9. Next IO job for 2nd job          at 15ms END at 29ms

CPU time is 3+5+4 =12ms

Total execution time = 29ms

CPU utilization = 12*100/29= 41.379%

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Answer:

Option B i.e., mdsswitch# show Vsan membership is the correct option.

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