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posledela
4 years ago
15

Give the spectator ions for the reaction that occurs when aqueous solutions of H2SO4 and KOH are mixed.

Chemistry
1 answer:
svet-max [94.6K]4 years ago
4 0

Answer:

Option C. K⁺(aq) and SO₄²¯(aq)

Explanation:

We'll begin by writing the ionic equation between H₂SO₄ and KOH.

This is illustrated below:

In solution, H₂SO₄ and KOH will dissociate as follow

H₂SO₄ (aq) —> 2H⁺ (aq) + SO₄²¯ (aq)

KOH (aq) —> K⁺ (aq) + OH¯ (aq)

Thus, aqueous H₂SO₄ and KOH will react as follow:

H₂SO₄ (aq) + 2KOH (aq) —> K₂SO₄ (aq) + 2H₂O (l)

Ionically:

2H⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> 2K⁺(aq) + SO₄²¯(aq) + 2H₂O (l)

The spectator ions are those ions that appear on both sides of the equation.

From the above ionic equation, the spectator ions are:

K⁺(aq) and SO₄²¯(aq)

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if I add 1.50 L of water to 250 mL of a 12.5 M NaOH solution, what will the molarity of the diluted solution be?
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Explanation:

Dilution is a process in which you always start with a concentrated solution to which a greater volume of solvent is added. This modifies the concentration and volume of the resulting solution, but the amount of solute used to prepare the initial solution remains the same.

In summary, in a dilution the amount of solute does not vary, but the volume of the solvent varies: when more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

The following rule is fulfilled:

Vinicial x Cinicial = Vfinal x Cfinal

where:

  • Vinicial = Initial volume.
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  • Cfinal = Final concentration

In this case:

  • Vinicial= 250 mL= 0.25 L (Being 1 L=1000 mL)
  • Cinicial= 12.5 M
  • Vfinal= 1.5 L+ 0.25 L=1.75 L
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Replacing:

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