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slega [8]
4 years ago
8

Differences in frames of reference are especially significant when ________. a. working on improving one’s listening skills b. c

ommunicating with people from different cultures c. overcoming physical barriers to communication
Chemistry
1 answer:
OlgaM077 [116]4 years ago
4 0

Answer:

hi :3

Explanation:

vghvhmg

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1. Look up an MSDS of the chemical HCl. What are the major hazards and what precautions would you take when handling this chemic
evablogger [386]

Answer:

Explanation:

The MSDS is Material Safety Data Sheet of HCl. Among the major hazards of hydrochloric acid is corrosive and irritant to skin and eye contact. Permanent damage may be in case.

What are the precautions to be taken while handling chemicals?

General rules for handling chemicals

Do not return chemicals to their original packaging. ...

Keep chemical containers closed. ...

Never use a wrong or an unmarked reagent. ...

Never put spatulas, stirrers or other objects into a storage container for chemicals.

What are the major hazards and what precautions would you take when handling HCl?

.Handling. Wear a chemical-resistant apron, chemical-resistant gloves and chemical splash goggles at all times when handling HCl to protect your eyes and skin. Concentrated hydrochloric acid is toxic if inhaled, so avoid breathing it in and always handle it while under a fume hood.

Hopes this Helps :D

Mark me Brainliest :)

3 0
2 years ago
HELP DUE SOON!
son4ous [18]
I believe the answer is B, or option 2. It makes the most sense, and is a fact.
4 0
2 years ago
A gas sample in a rigid container at 455 K is brought to STP (273K and 1 atm). What was the original pressure of the gas in mmHg
Molodets [167]
1) V(CH₄) = 0,376 L.T(CH₄) = 304 K.p(CH₄) = 1,5 atm 101325 Pa/atm = 151987,5 Pa = 151,9875 kPa.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(CH₄) = p · V ÷ R · T.n(CH₄) = 151,9875 kPa · 0,376 L ÷ 8,314 J/K· mol · 304 K.n(CH₄) = 0,0226 mol.V(CH₄) = n(CH₄) · Vm.V(CH₄) = 0,0226 mol · 22,4 dm³/mol.V(CH₄) = 0,506 dm³ = 0,506 L.
2) V(SO₂) = 5,2 L.p(SO₂) = 45,2 atm = 45,2 atm · 101,325 kPa/atm = 4579,89 kPa.T(SO₂) = 293 K.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(SO₂) = p · V ÷ R · T.n(SO₂) = 4579,89 kPa · 5,2 L ÷ 8,314 J/K· mol · 293 K.n(CH₄) = 9,77 mol.There is not enogh SO₂, 225 mol - 9,77 mol = 215,23 mol is needed.
3) p(He) = 3,50 atm · 101,325 kPa/atm = 354,63 kPa.V(He) = 4,00 L.n(He) = 0,410 mol.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.T = p · V ÷ R · n.T(He) = 354,63 kPa · 4,00 L ÷ 8,314 J/K· mol · 0,410 mol.T(He) = 416,14 K.n - amount of substance.
4) p(Ar) = 1,00 atm · 101,325 kPa/atm = 101,325 kPa.V(Ar) = 3,4 L.T(Ar) = 263 K.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(Ar) = p · V ÷ R · T.n(Ar) = 101,325 kPa · 3,4 L ÷ 8,314 J/K· mol · 263 K.n(Ar) = 0,157 mol.n(Ar) = 0,157 mol + 2,5 mol = 2,657 mol.p(Ar) = 2,657 mol · 8,314 J/K· mol · 263 K ÷ 3,4 L.p(Ar) = 1708,74 kPa.
6 0
4 years ago
Is carbon dioxide formed during incomplete combustion of methane? ...?
dexar [7]
Incomplete combustion<span> occurs when the supply of air or oxygen is poor. Water is still </span>produced<span>, but </span>carbon<span> monoxide and </span>carbon<span> are </span>produced<span> instead of </span>carbon dioxide<span>. The </span>carbon<span> is released as soot. </span>Carbon<span> monoxide is a poisonous gas, which is one reason why </span>complete combustion<span> is preferred to </span>incomplete combustion<span>.</span>
8 0
4 years ago
Read 2 more answers
Does the surface of the Earth always stay the same? Explain.
Daniel [21]

Answer:

The answer is no.

Explanation:

The surface of earth does not always stay the same as we know earth constantly moves and the surface of earth is constantly remodeled by various geological processes.

6 0
3 years ago
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