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3 years ago

Which reaction leads to the formation of a precipitate?

Chemistry

2 answers:

scoray [572]3 years ago

7 0

Answer: $2Ca(OH)_2(aq)+2FeCl_3(aq)\rightarrow CaCl_2(aq)+2Fe(OH)_2(s)$

Explanation: A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The reactions in which one of the product is formed as a solid are called as precipitation reactions.

a) $2Cr(NO_3)_3(aq)+3FeSO_4(aq)\rightarrow Cr_2(SO_4)_3(aq)+3FeNO_3(aq)$

b) $2RbF(aq)+CuSO_4(aq)\rightarrow Rb_2(SO_4)(aq)+CuF_2(aq)$

c) $2Ca(OH)_2(aq)+2FeCl_3(aq)\rightarrow CaCl_2(aq)+2Fe(OH)_2(s)$

Brrunno [24]3 years ago

6 0

2Ca(OH)2(aq) + 2FeCl3(aq) on the dead locs

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Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.

topjm [15]

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

$\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}$

Now put all the given values in this formula, we get the moles of calcium hydroxide.

$\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole$

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0

3 years ago

A person's blood type is determined by the presence and absence of specific antigens on the cell membrane. Which of these would

sukhopar [10]

Answer:

C - no antibodies

Explanation:

I dont think there is any blood type without antibodies

5 0

3 years ago

Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each

Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0

3 years ago

Think of a substance that does not dissolve in water. Any Examples?

worty [1.4K]

Answer:

sand, flour, water

Explanation:

7 0

3 years ago

Read 2 more answers

How many grams of potassium benzoate trihydrate, KC H302 - 3H20. are needed to prepare 1.5 L of a 0.120M solution of potassium b

Annette [7]

<u>Answer:</u> The mass of potassium benzoate is $8.40\times 10^{-4}g$

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

We are given:

Molarity of solution = 0.120 M

Molar mass of potassium benzoate trihydrate = 214.26 g/mol

Volume of solution = 1.5 L

Putting values in above equation, we get:

$0.120M=\frac{\text{Mass of potassium benzoate trihydrate}}{214.26\times 1.5}\\\\\text{Mass of potassium benzoate trihydrate}=\frac{0.120mol/L\times 1.5L}{214.26g/mol}=8.40\times 10^{-4}g$

Hence, the mass of potassium benzoate is $8.40\times 10^{-4}g$

8 0

3 years ago