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Dominik [7]
3 years ago
14

Which reaction leads to the formation of a precipitate?

Chemistry
2 answers:
scoray [572]3 years ago
7 0

Answer: 2Ca(OH)_2(aq)+2FeCl_3(aq)\rightarrow CaCl_2(aq)+2Fe(OH)_2(s)

Explanation: A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The reactions in which one of the product is formed as a solid are called as precipitation reactions.

a) 2Cr(NO_3)_3(aq)+3FeSO_4(aq)\rightarrow Cr_2(SO_4)_3(aq)+3FeNO_3(aq)

b) 2RbF(aq)+CuSO_4(aq)\rightarrow Rb_2(SO_4)(aq)+CuF_2(aq)

c) 2Ca(OH)_2(aq)+2FeCl_3(aq)\rightarrow CaCl_2(aq)+2Fe(OH)_2(s)

Brrunno [24]3 years ago
6 0

2Ca(OH)2(aq) + 2FeCl3(aq) on the dead locs

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Find the percent ionization of a 0.337 m hf solution. the ka for hf is 3.5 x 10-4. 1.1 % 1.2 x 10-2 % 3.2 % 3.5 x 10-2 % 4.7 %
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To determine the percent ionization of the acid given, we make use of the acid equilibrium constant (Ka) given. It is the ration of the equilibrium concentrations of the dissociated ions and the acid. The dissociation reaction of the HF acid would be as follows:<span>

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The acid equilibrum constant would be expressed as follows:

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To determine the equilibrium concentrations we use the ICE table,
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I      0.337           0                 0
C      -x              +x               +x
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3.5 x 10-4 = [H+][F-] / [HF] 
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Solving for x,

x = 0.01069 = [H+] = [F-]

percent ionization = 0.01069 / 0.337 x 100  = 3.17%

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