Answer:
Step-by-step explanation:
9. Yes
10. No
11. No
12. Yes
13. Yes
14. No
The answer might be: d.) infinite.
Y=-x+1 is the correct slope-intercept form of the equation of the line that goes through (1,0).
Answer: Decreased by 12 students
Step-by-step explanation:
40-28=12
The horizontal distance from the helicopter to the landing pad is 1658.81 feet
<em><u>Solution:</u></em>
The figure is attached below
Triangle ABC is a rightangled triangle
A helicopter is flying at point A and landing pad is at point c
Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees
The helicopter is 1250 feet from the ground
Therefore, AB = 1250 feet
To find: horizontal distance from the helicopter to the landing pad
BC is the horizontal distance from the helicopter to the landing pad
BC = ?
By the definition of tan,
![tan \theta = \frac{opposite}{adjacent}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D)
![tan 37 = \frac{AB}{BC}\\\\tan 37 = \frac{1250}{BC}\\\\ 0.75355 = \frac{1250}{BC}\\\\BC = \frac{1250}{0.75355}\\\\BC = 1658.81](https://tex.z-dn.net/?f=tan%2037%20%3D%20%5Cfrac%7BAB%7D%7BBC%7D%5C%5C%5C%5Ctan%2037%20%3D%20%5Cfrac%7B1250%7D%7BBC%7D%5C%5C%5C%5C%200.75355%20%3D%20%5Cfrac%7B1250%7D%7BBC%7D%5C%5C%5C%5CBC%20%3D%20%5Cfrac%7B1250%7D%7B0.75355%7D%5C%5C%5C%5CBC%20%3D%201658.81)
Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet