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IRISSAK [1]
3 years ago
11

Paavo was reviewing a request by an executive for a new subnotebook computer. The executive said that he wanted USB OTG support

and asked Paavo’s opinion regarding its security. What would Paavo tell him about USB OTG security
Computers and Technology
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

Connecting a mobile device as a peripheral to an infected computer could allow malware to be sent to that device.

Explanation:

Since in the question it is mentioned that Paavo reviewed a request by an executive for subnotebook computer i.e new. but he needs to USB OTG support so it is a  USB i.e on the go that links the devices from one device to another

Therefore by links the mobile device to the computer i.e infected that allows malware we called virus so that we are able to send it to that device. By this,  he wants to tell about the USB OTG security

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D. The BIOS is activated by powering on the CPU.

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nexus9112 [7]

Answer:

Explanation:

The following code is written in Java and runs a thread every 45 seconds that adds the two counters together and saves them in an integer variable called register. Then prints the variable. If this code runs 5 times it automatically breaks the loop. This can be changed or removed by removing the breakLoopCounter variable.

 public static void add_Counters(int counterOne, int counterTwo) {

       int register = 0;

       int breakLoopCounter = 0;

       try {

           while (true) {

               register += counterOne + counterTwo;

               System.out.println(register);

               Thread.sleep(45000);

               breakLoopCounter += 1;

               if (breakLoopCounter == 5) {

                   break;

               }

           }

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5 0
3 years ago
% Do not modify CalculateSum function maxSum = CalculateSum(userNum1, userNum2, userNum3) maxSum = MaxValue(userNum1, userNum2)
sergeinik [125]

Answer:

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def MaxValue(userNum1, userNum2):

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Explanation:

This defines the function

def MaxValue(userNum1, userNum2):

This returns userNum2 if userNum2 is greater than userNum1

<em>    if userNum2>userNum1:</em>

<em>        return userNum2</em>

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<em>    else:</em>

<em>        return userNum1</em>

<em />

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