Answer:
ELECTRONICS
a range of frequencies within a given band, in particular that used for transmitting a signal.
2.
the energy or mental capacity required to deal with a situation.
Explanation:
Answer:
It would be to figure out what cancers someone could exactly so no need for a biopsy
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n;
double average,sum=0,x;
cout<<"enter the Value of N:";
// read the value of N
cin>>n;
cout<<"enter "<<n<<" Numbers:";
// read n Numbers
for(int a=0;a<n;a++)
{
cin>>x;
// calculate total sum of all numbers
sum=sum+x;
}
// calculate average
average=sum/n;
// print average
cout<<"average of "<<n<<" Numbers is: "<<average<<endl;
return 0;
}
Explanation:
Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.
Output:
enter the Value of N:5
enter 5 Numbers:20.5 19.7 21.3 18.6 22.1
average of 5 Numbers is: 20.44
Answer:
def prompt_number():
while True:
number = int(input("Enter a number: "))
if number >= 0:
break
return number
def compute_sum(n1, n2, n3):
total = n1 + n2 + n3
return total
n1 = prompt_number()
n2 = prompt_number()
n3 = prompt_number()
result = compute_sum(n1, n2, n3)
print(result)
Explanation:
Create a function named prompt_number that asks the user to enter a number until a positive number or 0 is entered and returns the number
Create a function named compute_sum that takes three numbers, sums them and returns the sum
Ask the user to enter three numbers, call the prompt_number() three times and assign the values
Calculate the the sum, call the compute_sum and pass the numbers as parameters
Print the result
