To be able to identify that the object is in the same motion, we should find the graphs that has an increasing slope of displacement and with the constant velocity with varying time. Graphs on letter D satisfies these requirements.
<em>ANSWER: D</em>
Answer:
1. 20.54m/s
2. 1.52s
Explanation:
QUESTION 1:
The speed the stone impact the ground is the final speed/velocity, which can be calculated using the formula:
v² = u² + 2as
Where;
v = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration due to gravity (m/s²)
s = distance (m)
From the provided information, u = 5.65m/s, v = ?, s = 19.9m, a = 9.8m/s²
v² = 5.65² + 2 (9.8 × 19.9)
v² = 31.9225 + 2 (195.02)
v² = 31.9225 + 390.04
v² = 421.9625
v = √421.9625
v = 20.5417
v = 20.54m/s
QUESTION 2:
Using v = u + at
Where v = final velocity (m/s) = 20.54m/s
t = time (s)
u = initial velocity (m/s) = 5.65m/s
a = acceleration due to gravity (m/s²)
v = u + at
20.54 = 5.65 + 9.8t
20.54 - 5.65 = 9.8t
14.89 = 9.8t
t = 14.89/9.8
t = 1.519
t = 1.52s
And I gather that instead of trying it on your own, you want me to do it for you.
The force of gravity between two objects always involves the product of
both of their masses.
"Weight" is the force of gravity between a planet and an object on its surface,
so it depends on both masses.
When a rock, a space probe, or an astronaut goes to a different planet, its/his
mass doesn't change, but the mass of the body they're standing on is different.
So the weight of the rock or the astronaut is different from what it is on Earth.
First let’s pick one at random
Less than 5 percentile
That means they lined 100 kids up and less than 5% of them are that certain weight.
So if you apply this to every option you will see the answer is
A). Less than 5 percentile
The final velocity is half of train car B's initial velocity.
