The centripetal acceleration = 236.63 m/s²
The force = 17.98 N
<h3>Further explanation</h3>
Given
mass = 76 g = 0.076 kg
r = 1.5 m
f = 2 rps = 2 rotation per second
Required
The centripetal acceleration
The Force tension
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
The speed that is in the direction of the circle is called linear velocity
Can be formulated:
r = circle radius
f = rotation per second (RPS)
The linear velocity : 2 x 3.14 x 1.5 x 2 =18.84 m/s
The centripetal acceleration : ac = v²/R = 236.63 m/s²
The force : F = m x ac = 0.076 x 236.63 = 17.98 N
<u>Answer:</u>
<em>Sand in a beach is warmer than the water of the sea.
</em>
<u>Explanation:</u>
<em>Water absorbs less heat from the sun</em> when compared with sand. Sand is darker and also is less reflective. Because of its darker nature, absorption of heat from the sun will be more. Due to its less reflective nature the sand wouldn’t be able to<em> reflect off the sunlight.
</em>
But water is highly reflective and can reflect off a <em>major portion of the sunlight falling on the sea</em>. The sea is also deep and thus the heat spreads through a large volume unlike in the <em>case of sand.</em> Water also has the nature of constant movement unlike sand which is stable.
<em>This factor also heats up sand more than water.
</em>
Answer:
Explanation:
Assume the rod is horizontal
Sum vertical forces to zero
F - 8 - 4 - 2 - 3 = 0
F = 17 N
While this result answers precisely the question asked, it is not sufficient to guarantee equilibrium. We must also locate this force by summing moments to zero. Let's choose to sum about the left end.
8[9/2] + 4[1] + 2[6] + 3[4] - 17[x] = 0
x = 3.76470588...
the force must be supplied upward approximately 3.765 m from the left end
The rod does not actually have to be horizontal. Moment arms will all be proportionately reduced by tilting the bar from horizontal and the results will be identical. Assuming horizontal just reduces the calculation effort.
Answer:
The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
Explanation:
Given that,
Mass of the meter stick, m = 0.3 kg
Center of mass is located at its 45 cm mark.
We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :
or
So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
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