1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmasim [6.3K]
2 years ago
11

Gina is driving her car down the street. She has a teddy bear sitting on the back seat. A dog runs in front of Gina's car, so sh

e quickly applies the brakes. The force of the brakes causes the car to stop, but the teddy bear continues to move forward until it hits the car's dashboard. The teddy bear did not stop at the same time as the car because A. Objects in motion tend to stay in motion unless acted upon by an outside force. B. More force is required to stop softer objects than to stop harder objects. C. Only objects touching the Earth's surface can be acted upon by an outside force. D. Objects in motion can only be stopped by the application of a balanced force.
Physics
1 answer:
Elza [17]2 years ago
6 0

Answer:

A

Explanation:

A. Objects in motion tend to stay in motion unless acted upon by an outside force.

You might be interested in
When will the human population stop growing?
o-na [289]
I think it’s when the sun explodes because since we need to the sun I think the human population will fall out. also a huge war, a meteoroid huge as the one that killed the dinosaurs comes down, there is so much ways on how the human population can stop growing. hope this help at least!
5 0
2 years ago
Read 2 more answers
Zeros between a decimal point and a non-zero number are <br> (blank) significant
ipn [44]
<span>Zeros between a decimal point and a non-zero number are *radical numbers*
:) Hope this helps :)</span>
3 0
3 years ago
A box is sliding down an incline tilted at a 16.0 angle above horizontal. The box is initially sliding down the incline at a spe
blsea [12.9K]

Answer:

d) 1.44m

Explanation:

According to Newton's second law:

\sum F=m.a\\

analyzing the horizontal components of the force:

\sum F_x=mg*sin(\theta)-\µ*m.g*cos(\theta)\\\sum F_x=m*9.8*(sin(16^o)-0.420*cos(16^o))\\\sum F_x=-1.25m

applying the second law

-1.25m=m.a\\a=-1.25m/s^2

given the acceleration we can calculate the distances traveled before stopping:

(v_f)^2=(v_o)^2+2.a.\Delta x\\0=(1.90m/s)^2-2(1.25)*\Delta x\\\Delta x=1.44m

8 0
3 years ago
Consider the diagram of a pendulum's motion shown above. A pendulum can be used to model the change from potential energy
ivann1987 [24]

Answer: D

Explanation: Potential stores Kinetic Energy so, Point C will have Kinetic turned into Potential.

3 0
2 years ago
A gymnast jumps directly up onto a beam that is 1.5 m high. From the beam, she jumps 0.5 m straight up and lands back on the bea
tatiyna

Answer:

D. 2.5 m

Explanation:

1.5 m up to the beam + 0.5 m up + 0.5 m down = 2.5 m total

5 0
3 years ago
Other questions:
  • A ball rolls down a hill, starting from rest. How long is it rolling if it accelerates at 3m/s2 and ends with a velocity of 35m/
    6·1 answer
  • A constant force of 40N acting on a body initially at rest gives it an acceleration of 0.1m/s inverse 2 for 4s .calculate the wo
    13·1 answer
  • A wire is formed into a circle having a diameter of 11.1 cm and is placed in a uniform magnetic field of 2.79 mT. The wire carri
    15·1 answer
  • In your own words, describe the purpose of using a chemical equation.
    14·2 answers
  • State whether the light from an object moving towards us will be red shifted or blue shifted and explain why.
    12·1 answer
  • Help please 10 pts and quick!<br><br> can someone write me a short response
    13·1 answer
  • Given a force of 88n and an acceleration of 4m/s2 what is the mass​
    14·1 answer
  • In the center of the Milky Way galaxy is a<br> A
    11·2 answers
  • Will give
    13·2 answers
  • Explain how horizontal motion can be uniform while vertical motion is accelerated.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!