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Natali [406]
2 years ago
15

What is the solution to –2(8x – 4) < 2x + 5?

Mathematics
1 answer:
zhuklara [117]2 years ago
7 0

the answer is x > 1/6

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Please help me fast!!
elixir [45]

Answer:

y = -\frac{1}{4}x

Step-by-step explanation:

1. The slope-intercept form of a linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = slope.

2. To find the slope, let's take the two points (0,0) and (-40,10). After that, let's plug in the values to their corresponding variable in the formula: \frac{y_2-y_1}{x_2-x_1}

  • \frac{10-0}{-40-0}
  • \frac{10}{-40}
  • -\frac{1}{4}

3. Since we now know our slope, the equation looks like this so far: y = -\frac{1}{4}x + b.

4. Because b is the y-intercept, b = 0 because the line intersects the y-axis at (0,0).

5. Now that we have the values of m and b, we plug in them to get the equation of: y=-\frac{1}{4}x

3 0
2 years ago
Can you solve any of these geometry problem?
Fudgin [204]

Answer:

1. I don't know how to solve that sorry :(

2. B. It is a diameter

3. 30° = q

4. I don't know sorry :(

Step-by-step explanation:

1. I don't know how to solve that sorry :(

-----------------------------------------------------------

2. B. It is a diameter

------------------------------------

3. All triangles = 180°

180° = 60° + 90° + q

180° = 150° + q

180° - 150° = 150° - 150° + q

30° = q

180° = 60° + 90° + 30°

180° = 150° + 30°

180° = 180°

------------------------------------------

4. I don't know sorry :(

7 0
3 years ago
Find the area of the shape
Gwar [14]

Answer:

3pi

Step-by-step explanation:

First find the area of the entire circle

A = pi r^2

A = pi * 2^2

A = 4 pi

We know that this is 3/4 of a circle so multiply the area by the fraction of the circle

3/4 * 4 pi

3 pi

4 0
3 years ago
Read 2 more answers
R = sec(θ) − 2cos(θ), where -π/2 &lt; θ &lt; π/2
Alex

Answer:

  y = (x/(1-x))√(1-x²)

Step-by-step explanation:

The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:

  x = r·cos(θ)

  y = r·sin(θ)

  x² +y² = r²

__

  r = sec(θ) -2cos(θ)

  r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)

  r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²

  (x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations

  x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor

  y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

  \boxed{y=\dfrac{x\sqrt{1-x^2}}{1-x}}

__

The attached graph shows the equivalence of the polar and rectangular forms.

4 0
2 years ago
What are the roots of y=x^2+3x-10
USPshnik [31]
The answer is x = 2, -5
5 0
2 years ago
Read 2 more answers
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