Explanation:
The given data is as follows.
Air is at 
and 14.6 psia.
= 0.00015 ft, Flow rate, (Q) = 48000 
(a) Formula to calculate hydraulic radius 
is as follows.
= 
= 
ft
Formula for equivalent diameter is as follows.
= 
= 
ft
(b) Formula for velocity floe is as follows.
Q = VA
V = 
= 
ft/min
= 24000 ft/min
(c) Formula to calculate Reynold's number is as follows.
= 
= 
(as 
and 
= 0.0443 lb/ft. hr)
= 53742.66 hr/min
As 1 hr = 10 min. So, 
= 3224559.6
(d) Formula to calculate pressure drop 
is as follows.
Putting the given values into the above formula as follows.
= 
= 6.238 
Answer : The enthalpy of the reaction is, -2552 kJ/mole
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given enthalpy of reaction is,
The intermediate balanced chemical reactions are:
(1) 
(2) 
(3) 
(4) 
Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :
(when we are reversing the reaction then the sign of the enthalpy change will be change.)
The expression for enthalpy of the reaction will be,
Therefore, the enthalpy of the reaction is, -2552 kJ/mole
It would weigh more: the more mass an object has the more weight is added
The reaction is exothermic, the energy in the bonds has been released to the surroundings (causing the potential energy to go down). The increase in energy in the surrounding heats them up hence exothermic.
