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nexus9112 [7]
2 years ago
13

Energy 1:Question 3

Chemistry
1 answer:
liberstina [14]2 years ago
3 0

Answer: The statement, atoms in the sand were moving more quickly best describes why the  temperature of the sand increased.

Explanation:

As Sun rises in the morning everyday and the heat energy radiations given by the Sun falls on a number of objects on our surroundings. As a result, the objects absorb this heat energy till afternoon due to which they become hot.

Hence, atoms of the objects gain kinetic energy due to which they move quickly. This shows that the temperature of the object (sand here) increases.

When Maria walked in the same area in the afternoon, the sand was hot as its particles have gained kinetic energy due to which they move rapidly from one place to another. Hence, sand feels more hot in the afternoon in the same area where she walked.

Thus, we can conclude that the statement the atoms in the sand were moving more quickly best describes why the  temperature of the sand increased.

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Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M
liberstina [14]

Answer:

= \mathbf{C_3H_6O}

Explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

So, by applying the 13th rule;

we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r =  no. of hydrogen.

So;

\dfrac{58}{13}= 4 \ remainder \ 6

So;

C_nH_{n+r} = C_4H_{4+6}

= C_4H_{10}

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing CH_4. Also, since the mass is an even number then Nitrogen is 0.

So, we have:

= \mathbf{C_3H_6O}

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2 years ago
Give two test substances that would react with each other to produce salt and water​
Mademuasel [1]

Answer:

NaOH +HCl==>Nacl+H2O

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3 years ago
Is this statement true or false? Bases feel slippery. A. True B. False
Ksenya-84 [330]
Actually, it is true

7 0
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An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

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8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

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