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Nookie1986 [14]
4 years ago
8

Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!!

Mathematics
1 answer:
insens350 [35]4 years ago
4 0

The area of a right triangle with side lengths 7 and 7 is \frac{bh}{2} = \frac{7*7}{2} = \frac{49}{2} = 24.5

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Why was Copernicus' work controversial?
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Copernicus proposed a heliocentric model in which the earth revolved around the sun, not the other way, and this went against what the church was saying at the time: the church, which insisted it is always right, said that the sun revolver around the earth.


The correct answer is: <span>C. His scientific discoveries undermined the power of the Church. </span>
5 0
3 years ago
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2y+x=-8. Solve for y
gayaneshka [121]

Answer:

y = -\frac{1}{2}x - 4

Step-by-step explanation:

2y + x = -8

2y = -x - 8

\frac{2y}{2} = \frac{-x - 8}{2}

y = -\frac{1}{2}x - 4

6 0
3 years ago
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What is the equation that has a slope of −2 and passes through the point (1, −6)?
Agata [3.3K]

Answer:

y=-2x-4

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Just plugged in the points on desmos and then I just picked random points until they hit the point they wanted.

6 0
3 years ago
Please<br> <img src="https://tex.z-dn.net/?f=%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%28n%2B1%29%21%7D%7Bn%21-%28n%2B1%
Nana76 [90]
Hi there!
We are given the function - 
\lim_{n \to \infty} \frac{(n+1)!}{n!-(n+1)!}
and are told to find the limit of the function. 
The limit would be n approaches infinity, giving us an answer of -1. 
Here is how you solve this:
\frac{(n+1)!}{n!-(n+1)!}
Divide by (n + 1)! - 
\frac{1}{\frac{1}{n+1}-1 }
Now, we can refine the function - 
\lim_{n \to \infty}\frac{1}{\frac{1}{n+1}-1 }
Now, just simplify. This gives us - 
\lim_{n \to \infty} (1)
We can use the rule \lim_{x \to a}c=c to simplify the whole thing to get 1. Finally, we plug it back into our second derived equation to get 1/-1, which simplifies to -1. Therefore, the answer is -1. Hope this helped and have a great day!


3 0
3 years ago
I don’t understand the symbols in number 5 please
ValentinkaMS [17]

Binary Operations

The union of two sets A and B is denoted A ∪ B and

is defined as A ∪ B = {x|x ∈ A or x ∈ B}.

The intersection of two sets A and B is denoted A∩B

and is defined as A ∩ B = {x|x ∈ A and x ∈ B}.

Two sets are disjoint if they have no elements in common,

that is, A and B are disjoint if A ∩ B = ∅.

5 0
3 years ago
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