Answer:
Lawns ---Earnings
1 ----------------- 10
2 ----------------- 20
3 ----------------- 30
5 ----------------- 50
Step-by-step explanation:
Given
Earnings = $10 per lawn
Required
Complete the table
Let y be the earnings for x number of lawns
Since he earns $10 per x lawns, then the expression is:
To complete the table, we have the following:
When x = 1
When x = 2
When x = 3
When x = 5
So, the complete table is:
Lawns ---Earnings
1 ----------------- 10
2 ----------------- 20
3 ----------------- 30
5 ----------------- 50
Answer:
Area of square = 28.09 square cm.
Step-by-step explanation:
Given : A square has sides 5.3 cm long.
To find : Work out the area of the square.
Solution : We have given
Side of square = 5 .3 cm .
Area of square = side * side .
Area of square = 5.3 * 5.3 .
Area of square = 28.09 square cm.
Therefore, Area of square = 28.09 square cm.
Answer:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Step-by-step explanation:
We want to evaluate ![[11.5-(2.5*3)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2)
Let us evaluate within the parenthesis first:
![[11.5-(2.5*3)]^2=[11.5-(7.5)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-%287.5%29%5D%5E2)
![\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2](https://tex.z-dn.net/?f=%5Cimplies%20%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-7.5%5D%5E2)
We again subtract within the bracket to obtain:
![[11.5-(2.5*3)]^2=[4]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B4%5D%5E2)
This finally gives us:
Answer:
The GPA you earn in a particular semester is your Marginal GPA, and your cumalative GPA for all completed semesters is your average GPA.
Step-by-step explanation:
Original bill is 100%/20% *5.8=29
(dollars)
