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GrogVix [38]
3 years ago
11

In a roller-skating rink, the skaters all move at different speeds. Most skate slightly faster or slower than others, but someti

mes an adventuresome skater accelerates to an "outlying" speed that is much higher than that of everyone else, causing a hazard. As a result, skating rinks often post a sign that says:
Any skater moving faster than the average speed of all the skaters will be asked to leave the rink.

It is clear what the sign means, but it is statistically nonsensical. If there are 150 skaters in the rink, all skating at slightly varying speeds, what is the best estimate for how many of them are moving faster than the average speed of all the skaters?
A. 100
B. 0
C. 25
D. 75
E. 50
Mathematics
1 answer:
Stella [2.4K]3 years ago
4 0
I think the answer is c. 25

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Step-by-step explanation:

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At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T
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Answer:

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

To find the approximate area of side walk let us substitute pi equals 3.14.

\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Therefore, the approximate area of the side walk is 125.6\text{ m}^2.

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The sum of the probabilities in a probability distribution is always 1.

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