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Nadusha1986 [10]
4 years ago
7

Help, please. Ty if you do :D

Mathematics
2 answers:
Alik [6]4 years ago
5 0
I think is answer B
Readme [11.4K]4 years ago
5 0
Correct answer is D






Have a nice day
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Which ordered pair is a solution to the system of equations y=x+3 and y=x^2-x
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For this case we have the following system of equations:

y = x + 3\\y = x ^ 2-x

Equating the equations we have:

x ^ 2-x = x + 3\\x ^ 2-x-x-3 = 0\\x ^ 2-2x-3 = 0

To find the solutions we factor the equation. To do this, we look for two numbers that, when multiplied, result in -3 and when added, result in -2.

These numbers are: -3 and +1

-3 + 1 = -2\\-3 * (+ 1) = - 3

Thus, the factored equation is:

(x-3) (x + 1) = 0

Then, the solutions for the variable "x" are:

x_ {1} = 3\\x_ {2} = - 1

We find the solutions for the variable "y":

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(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

ANswer:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

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What times x gives us y?

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