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3 years ago

What part of the atmosphere contains dust, water vapor, and 75% of all gases

Physics

2 answers:

Alexeev081 [22]3 years ago

7 0

Answer:

Troposphere

Explanation:

Our atmosphere yay

tatyana61 [14]3 years ago

6 0

Answer: our troposphere

Explanation:

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olga nikolaevna [1]

Answer:

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3 years ago

In Fraunhofer diffraction wave front used is __________. A. Spherical B. Circular C. Plane D. Conical

Zepler [3.9K]

I am pretty sure the answer is C.

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3 years ago

A 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. What happens t

olya-2409 [2.1K]

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3 years ago

Read 2 more answers

A non uniform rod has mass

Doss [256]

Answer:

$r_{cm} = L/3$

Explanation:

Mass: M, Length: L.

$\sigma (x) = b(L-x)$

The formula that gives center of mass is

$\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2 + ...}{m_1 + m_2 + ...} = \frac{\Sigma m_i \vec{r}_i}{\Sigma m_i}$

In the case of a non-uniform mass density, this formula converts to

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx }$

where the denominator is the total mass and the nominator is the mass times position of each point on the rod.

We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx } = \frac{\int\limits^L_0 {xb(L-x)} \, dx }{\int\limits^L_0 {b(L-x)} \, dx } = \frac{b\int\limits^L_0{(xL - x^2)} \, dx }{b\int\limits^L_0 {(L-x)} \, dx } = \frac{\frac{x^2L}{2} - \frac{x^3}{3}}{Lx - \frac{x^2}{2}}\left \{ {{x=L} \atop {x=0}} \right.$

Here x's are cancelled. Otherwise, the denominator would be zero.

$r_{cm} = \frac{\frac{xL}{2}-\frac{x^2}{3}}{L-\frac{x}{2}}\left \{ {{x=L} \atop {x=0}} \right. = \frac{\frac{L^2}{2}-\frac{L^2}{3}}{L-\frac{L}{2}} = \frac{\frac{L^2}{6}}{\frac{L}{2}} = \frac{L}{3}$

8 0

3 years ago

What is an ideal gas?

Allisa [31]

An ideal gas is a theoretical gas composed of a set of point particles with random displacement, which do not interact with each other. The ideal gas concept is useful because it behaves according to the ideal gas law, a simplified equation of state, which can be analyzed using statistical mechanics.

The equation of state of a classical ideal gas is given by:

$PV=nRT$

Where:

P = pressure

V = Volume

n = amount of substance

T = Temperature

R = Ideal gas constant

7 0

1 year ago