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Ann [662]
3 years ago
5

The what is s measure of the number of waves that pass a point in a given amount of time

Physics
2 answers:
stepladder [879]3 years ago
5 0
The 'frequency' is the number of waves that pass a point in one second.

If the given amount of time is, say, 'Q' seconds, then the number of waves
that pass a point in the given amount of time is (Q) times (the frequency).
Charra [1.4K]3 years ago
4 0

<span>Frequency is the number of waves that pass a given point in a certain amount of time. </span>

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Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg
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To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

\omega = \frac{v}{R}

Where,

\omega =Angular velocity

v = Lineal Velocity

R = Radius

At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

\alpha = \frac{\omega}{t}

Where

\alpha =Angular acceleration

\omega = Angular velocity

t = Time

Our values are

v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})

v = 16.67m/s

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t=6s

Replacing at the previous equation we have that the angular velocity is

\omega = \frac{v}{R}

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\omega = 66.67rad/s

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

\alpha = \frac{\omega}{t}

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\alpha = 11.11rad/s^2

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