Question

Which equation can be solved to find one of the missing side lengths in the triangle? Triangle A B C is shown. Angle A C B is 90 degrees and angle C B A is 60 degrees. The length of side C B is a, the length of C A is b, and the length of hypotenuse A B is 12 units. cos(60o) = StartFraction 12 Over a EndFraction cos(60o) = StartFraction 12 Over b EndFraction cos(60o) = StartFraction b Over a EndFraction cos(60o) = StartFraction a Over 12 EndFraction

Answer 1

Answer:

D

Step-by-step explanation:

just took on edge

Answer 2

Answer:

The answer to your question is: letter D, last option

Step-by-step explanation:

Data

Triangle  ABC

∠C = 90°

∠B = 60°

CB = a

CA = b

hypotenuse (AB) = 12 units

Options

a) cos 60 = $\frac{12}{a}$   this equation is calculating secФ

b) cos 60 = $\frac{12}{b}$  this equation is determining csc Ф

c) cos 60 = $\frac{b}{a}$     this equation is determaning tanФ

d) cos 60 = $\frac{a}{12}$   this equation is determining cosФ,  so

                                                       this is the correct answer