F(x)=4x+1
g(x)=x^2-5
(f . g)(x)=?
(f . g)(x) = f(x) . g(x) = (4x+1).(x^2-5)=(4x).(x^2)+(4x).(-5)+(1).(x^2)+(1).(-5)
(f . g)(x) = 4x^(1+2)-20x+x^2-5
(f . g)(x)=4x^3+x^2-20x-5
Answer: Option A. 4x^3+x^2-20x-5
Answer:
Look at the pic I attached
Step-by-step explanation:
Answer:
A square root of a number is a value that, when multiplied by itself, gives the number.
Examples:
4 multiplied by itself is 16. Therefore, the square root of 16 is 4.
(4 x 4 = 16)
The same goes for every number.
(3 x 3 = 9) square root of 9 is 3
(5 x 5 = 25) square root of 25 is 5
5 because if you plug in to get the equation 3x+20=7x then subtract 3x from both sides and divide by 4 from both sides
The answer would be B, 5. Hope this helps!