In the past month, Ashley rented 3 video games and 1 DVD. The rental price for each video game was $2.70. The rental price for t
2 answers:
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Answer:
1/4 or 25%
Step-by-step explanation:
The probability for rolling an odd number is 50% or because there are 3 odd numbers, (1, 3, 5) and 6 total outcomes (1, 2, 3, 4, 5, 6).
The probability for rolling two odd numbers in a row is
So, the probability of rolling an odd number twice is 25% or .
<h2>Answer:</h2>
________________________________________________________
<h3>Transform the expression using the sum-to-product formula</h3>________________________________________________________
<h3>Combine like terms</h3>________________________________________________________
<h3>Divide both sides of the equation by the coefficient of variable</h3>________________________________________________________
<h3>Apply zero product property that at least one factor is zero</h3>________________________________________________________
<h2>Cos (8A/2) = 0:</h2><h3>Cross out the common factor</h3>________________________________________________________
<h3>Solve the trigonometric equation to find a particular solution</h3>________________________________________________________
<h3>Solve the trigonometric equation to find a general solution</h3>________________________________________________________
<h2>cos(-2A/2) = 0</h2><h3>Reduce the fraction</h3>________________________________________________________
<h3>Simplify the expression using the symmetry of trigonometric function</h3>________________________________________________________
<h3>Solve the trigonometric equation to find a particular solution</h3>________________________________________________________
<h3>Solve the trigonometric equation to find a general solution</h3>________________________________________________________
<h3>Find the union of solution sets</h3>________________________________________________________
<h2>A = π/8 + nπ/4 or A = π/2 + nπ, n ∈ Z</h2><h3>Find the union of solution sets</h3><em>I hope this helps you</em>
<em>:)</em>