3x+2(x-1)=9x=4
We move all terms to the left:
3x+2(x-1)-(9x)=0
We add all the numbers together, and all the variables
-6x+2(x-1)=0
We multiply parentheses
-6x+2x-2=0
We add all the numbers together, and all the variables
-4x-2=0
We move all terms containing x to the left, all other terms to the right
-4x=2
x=2/-4
x=-1/2
First, convert 5 and 24/10 into a mixed fraction:
5 and 24/10 = 74/10
Now, divide 74/10 by 4:
74/10 ÷ 4 = 74/10 × 1/4
= 74/40
= 37/20
= 1 and 17/20
(Remember that dividing requires you to reciprocate 4)
Hope this helps!
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
The answer is a rational number is one integer divided by
another, and can be represented in either decimal of fraction form. The explanation
behind this is visualize you are using long division to divide one number by one
more. You divide, and then you acquire a remainder. Then you carry down a
zero (multiply by ten) and divide again. Well, there are only so many balances
you could perhaps have. For example, for 5, your choices are 0, 1, 2, 3,
and 4. Sooner or later, you will replicate a remainder, at which fact you
will just keep dividing the same method you did last time you saw that
remainder -- and that's the reason why it repeats.