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LenaWriter [7]
3 years ago
12

Which statement is true regarding the graphed functions?

Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0

Answer:

probably b

Step-by-step explanation:

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Question 8 c
balandron [24]
22 total tokens

15/22 is the probability you won’t draw a red
7 0
2 years ago
Which of the following triangles are right triangles? select all apply
Alex Ar [27]

Answer:

The following Triangles are Right Triangles:

1.  Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

Step-by-step explanation:

For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.

i.e.

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

AC² = 365² = 133225

AB² + BC² = 76² + 357² = 1333225

∴  AC² = AB² + BC²

Hence Δ ABC a Right Triangle.

For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

MT² = 845² = 71405

MI² + IT² = 123² + 836² = 714025

∴ MT² = MI² + IT²

Hence Δ MIT a Right Triangle.

For  Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

ML² = 101² = 10201

ME² + EL² = 20² + 99² = 10201

∴ ML² = ME² + EL²

Hence Δ MEL a Right Triangle.

7 0
3 years ago
What are the solutions of 4x2 + x = -3? (5 points) and <br> x2 - 7x = -12 (5 points)
Yuki888 [10]
4x^2 + x + 3 = 0

x =  [-1 +/- sqrt (1^2 - 4 * 4 * 3)]  / 8 =  - 1 +/- sqrt ( --47) / 8

=  ( - 1 +/- sqrt47i) / 8  =  -0.125 + 0.857i ,  -0.125 - 0.857i
7 0
3 years ago
Read 2 more answers
From a candy machine a random handful of colored chocolate candies are dispensed with 2 quarters. In one turn the machine dispen
Gemiola [76]

Answer:

the answer should be 1/11

Step-by-step explanation:

p(blue first) = 3/12

p(yellow second) = 4/11

so p = 3/12 x 4/11

1/11 is your probability

8 0
2 years ago
Find the sum of<br>−3x2−x−10 and 10x^2+x-10
Andru [333]

<em>Look at the attached picture⤴</em>

<em>Look at the attached picture⤴Hope it will help u....:)</em>

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