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3 years ago

What would be the volume of a sample of Uranium with a mass of 1800g?

Chemistry

1 answer:

Yuki888 [10]3 years ago

5 0

Answer:

V = 94.24 cm3

Explanation:

Uranium metal has a very high density of 19.1 g/cm3.

d = 19.1 g/cm3

m = 1800 g

m = V × d

=> V = m/d = 1800/19.1 = 94.24 cm3

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dem82 [27]

Answer:

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2 years ago

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in order to make tea, 32,000 J of energy were added to 100.0g of water. what was the temperature Chang of the water?

mina [271]

Answer:

ΔT = 76.5 °C

Explanation:

Given data:

Amount of water = 100.0 g

Energy needed = 32000 J

Change in temperature = ?

Solution,

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = m.c. ΔT

ΔT = Q / m.c

ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C

ΔT = 32000 j / 418.4 j /°C

ΔT = 76.5 °C

5 0

3 years ago

The natural gas in a storage reservoir, under a pressure of 1.00 atmosphere, has a volume of 2.74 × 109 L at 20.0°C. The tempera

Soloha48 [4]

Answer : The final volume of gas will be, $2.36\times 10^9L$

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$\frac{V_1}{V_2}=\frac{T_1}{T_2}$

where,

$V_1$ = initial volume of gas = $2.74\times 10^9L$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $20.0^oC=273+20.0=293K$

$T_2$ = final temperature of gas = $-20.0^oC=273+(-20.0)=253K$

Now put all the given values in the above formula, we get the final volume of the gas.

$\frac{2.74\times 10^9L}{V_2}=\frac{293K}{253K}$

$V_2=2.36\times 10^9L$

Therefore, the final volume of gas will be, $2.36\times 10^9L$

8 0

3 years ago

The Handbook of Chemistry and Physics gives solubilities of the following compounds in grams per 100 mL water. Because these com

Elanso [62]

Answer:

(a) $Ksp=4.50x10^{-7}$

(b) $Ksp=1.55x10^{-6}$

(d) $Ksp=1.05x10^{-22}$

Explanation:

Hello,

In this case, given the solubility of each salt, we can compute their molar solubilities by using the molar masses. Afterwards, by using the mole ratio between ions, we can compute the concentration of each dissolved and therefore the solubility product:

(a) $BaSeO_4(s)\rightleftharpoons Ba^{2+}(aq)+SeO_4^{2-}(aq)$

$Molar\ solubility=\frac{0.0188g}{100mL} *\frac{1mol}{280.3g}*\frac{1000mL}{1L}=6.7x10^{-4}\frac{mol}{L}$

In such a way, as barium and selenate ions are in 1:1 molar ratio, they have the same concentration, for which the solubility product turns out:

$Ksp=[Ba^{2+}][SeO_4^{2-}]=(6.7x10^{-4}\frac{mol}{L} )^2\\\\Ksp=4.50x10^{-7}$

(B) $Ba(BrO_3)_2(s)\rightleftharpoons Ba^{2+}(aq)+2BrO_3^{-}(aq)$

$Molar\ solubility=\frac{0.30g}{100mL} *\frac{1mol}{411.15g}*\frac{1000mL}{1L}=7.30x10^{-3}\frac{mol}{L}$

In such a way, as barium and bromate ions are in 1:2 molar ratio, bromate ions have twice the concentration of barium ions, for which the solubility product turns out:

$Ksp=[Ba^{2+}][BrO_3^-]^2=(7.30x10^{-3}\frac{mol}{L})(3.65x10^{-3}\frac{mol}{L})^2\\\\Ksp=1.55x10^{-6}$

$Molar\ solubility=\frac{0.038g}{100mL} *\frac{1mol}{289.35g}*\frac{1000mL}{1L}=1.31x10^{-4}\frac{mol}{L}$

In such a way, as ammonium, magnesium and arsenate ions are in 1:1:1 molar ratio, they have the same concentrations, for which the solubility product turns out:

$Ksp=[NH_4^+][Mg^{2+}][AsO_4^{3-}]^2=(1.31x10^{-4}\frac{mol}{L})^3\\\\Ksp=2.27x10^{-12}$

(D) $La_2(MoOs)_3(s)\rightleftharpoons 2La^{3+}(aq)+3MoOs^{2-}(aq)$

$Molar\ solubility=\frac{0.00179g}{100mL} *\frac{1mol}{1136.38g}*\frac{1000mL}{1L}=1.58x10^{-5}\frac{mol}{L}$

In such a way, as the involved ions are in 2:3 molar ratio, La ion is twice the molar solubility and MoOs ion is three times it, for which the solubility product turns out:

$Ksp=[La^{3+}]^2[MoOs^{-2}]^3=(2*1.58x10^{-5}\frac{mol}{L})^2(3*1.58x10^{-5}\frac{mol}{L})^3\\\\Ksp=1.05x10^{-22}$

Best regards.

7 0

3 years ago

20 Points please help in return, brainliest and special thanks :)

Gnom [1K]

The answer is The molecule contains oxygen atoms. Because the two O means oxygen in the periodic table

8 0

3 years ago

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