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Leni [432]
3 years ago
10

What is past form of be​

Chemistry
2 answers:
Vsevolod [243]3 years ago
5 0
There technically isn’t one. “Were” would be closest
Eduardwww [97]3 years ago
5 0

Answer:

was or were

Explanation:

self explainitory

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What should you do if the high power objective lens touches or breaks the cover slip?
saul85 [17]
Tell your teacher. They'll know what to do and it's best to report it to them.
6 0
3 years ago
A student is building an electrical circuit. Which material should she choose for wires, and why.
r-ruslan [8.4K]

D. A metal such as copper, because its atom have very mobile electrons         - A-p-e-x verified!

<u>Have a Great Day!</u>

3 0
3 years ago
Draw the structure of the product of each step in the following three-step synthesis. Show the formal charges, if applicable. As
Dvinal [7]

Answer:

Second step: 4-bromo-1-methyl-2-nitrobenzene.

Third step: 1.5-dibromo-2-methyl-3-nitrobenzene.

Explanation:

To solve this exercise I will use the concepts of electrophilic substitution. In these reactions, a functional group is displaced by an electrophile. In the attached image are the two main products.

5 0
3 years ago
At a given temperature, the elementary reaction A ---&gt;B in the forward direction is first order in A with a rate constant of
Pani-rosa [81]

Answer:

The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.

The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.

Explanation:

For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).

Kc=\frac{kf}{ki} =\frac{1.60 \times 10^{2} s^{-1}   }{ 9.30 \times 10^{-2} s^{-1}} =1.72 \times 10^{3}

If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.

K'c=\frac{1}{Kc} =\frac{1}{1.72 \times 10^{3}  } =5.81 \times 10^{-4}

4 0
4 years ago
What volume is occupied by 0.102 molmol of helium gas at a pressure of 0.95 atmatm and a temperature of 305 kk ?
zalisa [80]

The volume occupied by 0.102 mole of the helium gas is 2.69 L

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Number of mole (n) = 0.102 moles
  • Pressure (P) = 0.95 atm
  • Temperature (T) = 305 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Volume (V) =?

<h3>How to determine the volume </h3>

The volume of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both sides by P

V = nRT / P

V = (0.102 × 0.0821 × 305) / 0.95

V = 2.69 L

Thus, the volume of the gas is 2.69 L

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

8 0
1 year ago
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