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lawyer [7]
3 years ago
12

What is the flexible connective tissue shown in blus?

Chemistry
2 answers:
Sliva [168]3 years ago
5 0

Answer:

cartilage

Explanation:

satela [25.4K]3 years ago
3 0
Have to b O muscle cartilage
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200 grams of an organic sample which contains only carbon, hydrogen and oxygen is analyzed and found to contain 97.30grams of ca
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The empirical formula is C2H4O
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Black_prince [1.1K]
Im confused here. Add the rest of the question for me to help you
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2 years ago
would you expect potassium to have a high electronegativity or a low electronegativity? explain your answer
GalinKa [24]

A low electronegativity

Explanation:

Potassium is a metal that is expected to have a very low electronegativity value.

Electronegativity is the relative tendency by which an atom attracts valence electrons in a chemical bond.

Potassium is an element in the first group on the periodic table.

The common trend is that electronegativity increases from left to right and decreases down a group.

  • Potassium as metal will prefer to lose electrons rather than attracting because that will make it achieve the octet configuration that will ensure its stability.
  • This is why it will have low electronegativity.

Learn more:

Electronegativity brainly.com/question/11932624

#learnwithBrainly

4 0
3 years ago
A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
3 years ago
What is the usual charge on an ion formed from an atom that originally had seven valence electrons?
motikmotik
Negative because it'll have to gain an electron
4 0
3 years ago
Read 2 more answers
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