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Klio2033 [76]
3 years ago
8

What is the area is sector GPH?

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

157 square yards

Step-by-step explanation:

Area of circle:

A = pie r^2

A = 3.14 * 15^2

A = 706.5 square yards

< GPH = 80° -->  360/80 = 4.5

Area of sector GPH = 706.5 / 4.5 = 157 square yards

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professor190 [17]
Fraction: 1/20
Decimal: 0.05
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4 years ago
Read 2 more answers
Need help with solving quadratics using the quadratic equation!
Charra [1.4K]
You need to solve the following equation:
-0.5x^2 +36x -161 = 451

Set right side to 0
-0.5x^2 +36x -612 = 0

Multiply by -2 to get rid of decimal and leading neg coefficient.
x^2 -72x + 1224 = 0

Use quadratic formula:
a = 1, b = -72, c = 1224

x = \frac{-(-72) \pm \sqrt{(-72)^2 -4(1)(1224)}}{2(1)} \\  \\ x = \frac{72 \pm \sqrt{288}}{2} \\  \\ x = 27.51, 44.49

Therefore the min price to have 451 profit is $27.51
3 0
3 years ago
16/20 =t + (- 13/20) help please what is t
Black_prince [1.1K]

Simplify brackets

16/20 = t + -13/20

Simplify 16/20 to 4/5

5/5 = t - 13/20

Add 13/20 to both sides

4/5 + 13/20 = t

Simplify 4/5 + 13/20 to 29/20

29/20 = t

Switch sides

<u>t = 29/20</u>

3 0
4 years ago
Write the equation on the line passing through the two points (-2,11) and (5,-3)
nalin [4]

Answer:

y = - 2x + 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 2, 11) and (x₂, y₂ ) = (5, - 3)

m = \frac{-3-11}{5+2} = \frac{-14}{7} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 11), then

11 = 4 + c ⇒ c = 11 - 4 = 7

y = - 2x + 7 ← equation of line

3 0
4 years ago
(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

4 0
3 years ago
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