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iragen [17]
2 years ago
13

Find the value of 2x+8y when X= -5 and y=6​

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
3 0

Answer:

30

Step-by-step explanation:

Substitute the x in the expression with a -5 and substitute the y in the expression with a 6

2(-5)+8(6)

-10+40

30

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Lol yes I can factor that. x^{4} -3)(x^{4}-4) But, this can be factored further. ( x^{2} -2)( x^{2} +2)( x^{4}-3)
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Find the radius.<br> 120°<br> Sector Area = 66.99
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radius = 7.998170905 or about 8 units of measurement

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PLEASE I NEED HELP QUICK:
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1/3 is 0.3333333 and you round it by the 3rd three, so it looks like 0.334
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Please help me with these. These are so hard.<br><br>​
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about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
3 years ago
5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ
mart [117]

Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

<em>Let </em>\hat p<em> = sample proportion</em>

The z-score probability distribution for sample proportion is given by;

               Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

           p = population proportion = 48%

           n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } } ) = P(Z < 0.89) = 0.8133

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>

Therefore, probability that the sample proportion will be greater than 0.50 is 0.8133.

6 0
3 years ago
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