Question

How do i find thr distance between eatch pair of points

Answer 1

Hi there!

Use th' following formula
To find the distance between each pair of pts. :-

$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

According to th' question :-

♦ (-2, -2) (-2, 10) :--

$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$\sqrt{(-2 + 2)^2 + (10 + 2)^2}$

$\sqrt{0^2 + 12^2}$

$\sqrt{12^2}$ = $\sqrt{144}$ = 12

Therefore,
distance between the following pts. is 12 units.

♦ (-5.3, -2.2) (-5.3, -8.7) :--

$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$\sqrt{(-5.3 + 5.3)^2 + (-8.7 + 2.2)^2}$

$\sqrt{0^2 + (-6.5)^2}$

$\sqrt{-6.5^2}$ = $\sqrt{42.25}$ = 6.5

Therefore,
distance between th' following pts. is 6.5 units.

~ Hope it helps!

Answer 2

$\sf Hello!$

$\sf To\: calculate\: the\: distance,$
$\sf We\: have$ :-

$\sf \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}$

Then,

(i) $\sf (-2, -2) and (-2, 10)$ :

⇒ $\sf \sqrt{(-2 + 2)^{2} + (10 + 2)^{2}}$

⇒ $\sf \sqrt{0^{2} + 12^{2}}$

⇒ $\sqrt{144}$ = $\sf 12$

$\sf Therefore,$
$\sf The\: distance\: is\: 12 \:units.$

(ii) $\sf (-5.3, -2.2) and (-5.3, -8.7)$

⇒ $\sf \sqrt{(-5.3 + 5.3)^{2} + (-8.7 + 2.2)^{2}}$

⇒ $\sf \sqrt{0^{2} + (-6.5)^{2}}$

⇒ $\sqrt{ 42.25}$ = $\sf 6.5$

$\sf Therefore,$
$\sf The\: distance\: is\: 6.5 \:units.$

~ $\sf iCarl$