The point translated up 7 and left 3. This will cause the point to go from (-3,7) to (-6,14)
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Step-by-step explanation:
perimeter=28
length=2x
width=x
28=2(x+2x)
28=2x+4x
28=6x
28/6=6x/6
4.67=x
width=4.67
length=2×4.67
=9.34
Answer:
Assume:
(angle) RSB and angle (LSA) = D
and (line) ASR and (line) LSB is striaght then
(9x +27) + D = 180
(6x + 66) + D = 180
9x + D = 153
6x + D = 114
substitute
6x + D = 114
D = 114 - 6 x
9x + (114 - 6x) =153
3x = 39
x = 13
D = 114 - 6(13)
D=36
Step-by-step explanation:
9514 1404 393
Answer:
83 m
Step-by-step explanation:
The attached diagram shows the lengths of the midlines to be 3.16 and 5.10 units on the coordinate plane. The sum of these is (3.16 +5.10) = 8.26 coordinate plane units. Since each unit on the coordinate plane represents 10 m, the total path length is about ...
8.26(10 m) = 82.6 m ≈ 83 m
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The distance formula will tell you the distances are ...
AC = √(3² +1²) = √10
BD = √(5² +1²) = √26
The total path length is about (10 m)(√10 +√26) ≈ 82.61230 m ≈ 83 m.