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AveGali [126]
3 years ago
6

How do I solve this -4y+x=-27

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0
According x variable;

-4y+x=-27\\
\\
\boxed{x=4y+27}

According y variable:

-4y+x=-27\\
\\
-4y=-27-x\\
\\
\boxed{y=\frac{-27-x}{-4}}
GrogVix [38]3 years ago
5 0
First you have to know what a "solution" is.

The 'solution' is a set of 2 numbers which, if you put them into the equation
in place of 'x' and 'y', make the equation a true statement. 

There are an infinite number of possible pairs of numbers that can do that. 
Here are a few:

x = 0, y = 6.75 
x = 1, y = 7
x = 2, y = 7.25
x = 3, y = 7.5
x = 4, y = 7.75
x = 10, y = 9.25
x= 100, y = 31.75
x= -50, y = -5.75

When you graph this equation, the graph is a straight line without any ends.
Every point on the line is a solution to the equation, and you know how many
points there are on a line without ends . . . . .



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lisabon 2012 [21]
You would need to remove (-2, 1)
8 0
3 years ago
Please help me answer number 4! And if you can, please explain!
Leno4ka [110]
If Nathan does 9 minutes of push ups for 3 days, that's 9 divided by 3, which is 3. (9/3=3)  So nathan does 3 minutes of push ups each day, so just multiply each day by 3 to find the correlation between the two.

The Table should look like this: 

# of days      # of Minutes
1                     3
2                     6
3                     9
4                     12
5                     15
6                     18 
7                     21

5 0
2 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
2 years ago
Write two mixed numbers that are equal to 7.5
joja [24]
Seven and one half or seven and eight sixteenths
7 0
3 years ago
Read 2 more answers
Help please! Thankyou
Soloha48 [4]

Answer:

Thus, option A is correct.

Explanation:

<u>match the proportions</u>

  • $240,000 → 60%
  • x → 100%

<u>set up a equation:</u>

\sf \dfrac{60}{100}  = \dfrac{240,000}{x}

\sf x = \$400,000

4 0
2 years ago
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