A 34.87 g sample of a substance is initially at 27.1 C. after absorbing 1071 J of heat, the temperature of the substance is 145.

0 C. what is the specific heat (SH) of the substance?
SH=___ J / g * C

Chemistry

1 answer:

Alenkinab [10]3 years ago

7 0

$H= \frac{1071}{34.87}*145\\H= \frac{155295}{34.87} \\H= \frac{15529500}{3487} \\H=4453.542$

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