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3 years ago

Applicable in case of strong acid–

Chemistry

1 answer:

liq [111]3 years ago

5 0

Answer:

A. i, ii, iii

Explanation:

A strong acid gets completely ionized in aqueous solutions releasing a large number of hydrogen ions. It also has a sour taste.

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Predict the chemical formula of butyne, having one carbon-carbon triple bond.

Svet_ta [14]

Butyne is the alkyne with four carbon atoms, and, as the question states, it has one carbon-carbon triple bond. The general formula of an alkyne is CnH2n-2, that means that when there are 2 carbons the formula is C2H2, when there are 3 carbons the formula is C3H4, and when there are 4 carbons the formula is C4H6. So, butyne is C4H6 or " CH3-C (triple bond) C - CH3" (note that I wrote the phrase triple bond between the two Cs in the middle of the formula because there is no way to draw the three hyphens stacked one over other").

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3 years ago

Why you think your claim is the best explanation for Jordan Jones’s improved performance?

ehidna [41]

Answer:

My claim gives reasoning

Explanation:

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3 years ago

Carbon monoxide gas reacts with hydrogen gas to form methanol via the following reaction: CO(g)+2H2(g)→CH3OH(g)CO(g)+2H2(g)→CH3O

zvonat [6]

Answer: The limiting reactant is hydrogen gas and the theoretical yield of methanol is 0.507 grams

Explanation:

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$ ..........(1)

For carbon monoxide:

We are given:

$P=232mmHg\\V=1.55L\\T=305K\\R=62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Putting values in equation 1, we get:

$232mmHg\times 1.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 305K\\\\n=\frac{232\times 1.55}{62.3637\times 305}=0.0189mol$

For hydrogen gas:

We are given:

$P=389mmHg\\V=1.55L\\T=305K\\R=62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Putting values in equation 1, we get:

$389mmHg\times 1.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 305K\\\\n=\frac{389\times 1.55}{62.3637\times 305}=0.0317mol$

For the given chemical equation:

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

By Stoichiometry of the reaction:

2 moles of hydrogen gas reacts with 1 mole of carbon monoxide

So, 0.0317 moles of hydrogen gas will react with = $\frac{1}{2}\times 0.0317=0.01585mol$ of carbon monoxide

As, given amount of carbon monoxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrogen gas produces 1 mole of methanol

So, 0.0317 moles of hydrogen gas will produce = $\frac{1}{2}\times 0.0317=0.01585moles$ of methanol

Now, calculating the mass of methanol from equation 1, we get:

Molar mass of methanol = 32 g/mol

Moles of methanol = 0.01585 moles

Putting values in equation 1, we get:

$0.01585mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.01585mol\times 32g/mol)=0.507g$

Hence, the limiting reactant is hydrogen gas and the theoretical yield of methanol is 0.507 grams

7 0

3 years ago

Quiénes son los expertos para hablarnos sobre alimentación?:

Fantom [35]

Answer:

es nutricionista el experto en esa area

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3 years ago

What is the trend in electropositivity in group 1 elements?

REY [17]

Explanation:

the trend in electropositivity in group 1

Li < Na < K < Rb < Cs

4 0

3 years ago