Y=2cos3x How do I graph this with labels in radians
1 answer:
Answer:
Linked an image
Step-by-step explanation:
Okay, basically since it is y=2co3x you know that the amplitude is 2, so rather than going to +1 and -1, you now go to +2 and -2. Since it's cosine, you also know that you start at the maximum rather than the intercept, so the starting point is at (0,2).
I'm assuming that you need to graph 2 periods, and to find the periods you divide 2pi/b, so, in this case, 2pi/3
Then lastly you need to find the four points between 0 and 2pi/3, so you divide 2pi/3/4 to get 2pi/12=pi/6
If you have any other questions just comment and I'll respond when I see it.
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The distance formula is given by 
Take point A(0, -7) as (x₁, x₂) and point B(8, 8) as (y₁, y₂)
Distance AB =
Distance AB =
Distance AB =
Distance AB = 17
The line AB is dilated to A'B' by scale factor of 2, it means the length of the line is multiplied by 2
Distance A'B' = 2 × 17 = 34 units
Take point A(0, -7) as (x₁, x₂) and point B(8, 8) as (y₁, y₂)
Distance AB =
Distance AB =
Distance AB =
Distance AB = 17
The line AB is dilated to A'B' by scale factor of 2, it means the length of the line is multiplied by 2
Distance A'B' = 2 × 17 = 34 units