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gavmur [86]
3 years ago
5

Y=2cos3x How do I graph this with labels in radians

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0

Answer:

Linked an image

Step-by-step explanation:

Okay, basically since it is y=2co3x you know that the amplitude is 2, so rather than going to +1 and -1, you now go to +2 and -2.  Since it's cosine, you also know that you start at the maximum rather than the intercept, so the starting point is at (0,2).  

I'm assuming that you need to graph 2 periods, and to find the periods you divide 2pi/b, so, in this case, 2pi/3

Then lastly you need to find the four points between 0 and 2pi/3, so you divide 2pi/3/4 to get 2pi/12=pi/6

If you have any other questions just comment and I'll respond when I see it.

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Select all polynomials that are divisible by (x-1).
goldenfox [79]

Answer:

The answer to your question is below

Step-by-step explanation:

*A(x)=3x³ + 2x² - x           This polynomial is not divisible by (x - 1)

                                       Factor completely    3x(x + 1)(3x - 1)

*B(x)=5x³ - 4x² - x            This polynomial is divisible by (x - 1)

                                       factor completely   3x(x - 1)(5x + 1)

*C(x)=2x³ - 3x² + 2x - 1     This polynomial is divisible by (x - 1)

                                        Synthetic division      2   - 3  + 2  -1      1

                                                                                   2    -1    1                

                                                                            2    -1      1    0

*D(x)=x³ + 2x² + 3x + 2   This polynomial is not divisible by (x - 1)

                                        Synthetic division    1    2   3   2   1

                                                                                1    3   6                      

                                                                           1    3   6   8                  

3 0
4 years ago
Determine the margin of error, m m , of a 90% confidence interval for the mean IQ score of all students with the disorder. Assum
Vsevolod [243]

Answer:

The margin of error is 6.45.

Step-by-step explanation:

The complete question is:

As an early intervention effort, a school psychologist wants to estimate the average score on the Stanford-Binet Intelligence Scale for all students with a specific type of learning disorder using a simple random sample of 36 students with the disorder.

Determine the margin of error, of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume that the standard deviation IQ score among the population of all students with the disorder is the same as the standard deviation of IQ score for the general population, σ = 15 points.

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

Given:

<em>n</em> = 36

σ = 15

(1 - <em>α</em>)% = 99%

Compute the critical value of <em>z</em> for 99% confidence level as follows:

z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

*Use a <em>z</em>-table.

Compute the value of MOE as follows:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

          =2.58\times\frac{15}{\sqrt{36}}

          =2.58\times 2.5\\=6.45

Thus, the margin of error is 6.45.

5 0
3 years ago
Line that is parallel to y= -3/2x-1
VLD [36.1K]

Answer:

See below.

Step-by-step explanation:

There is an infinite number of lines parallel to y = -3/2x - 1.

They have the same slope, -3/2, and a different y-intercept.

Examples:

y = -3/2x + 1

y = -3/2x

y = -3/2x - 5

6 0
3 years ago
Equation in point slope form for the line That passes through the given points (-4,6) (-2,22)
mr_godi [17]

Step-by-step explanation:

m=

\frac{y}{x}

=6÷-4

=-1.5

also

(-2,22)

=-2÷22

=-1.5909090

5 0
3 years ago
Which equation represents the line that passes through (-6, 7) and (-3, 6)?
Degger [83]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

(x_ {1}, y_ {1}): (- 6,7)\\(x_ {2}, y_ {2}): (- 3,6)

We find the slope of the line:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {6-7} {- 3 - (- 6)} = \frac {-1} {-3 + 6} = \frac {-1} {3} = -\frac {1} {3}

Thus, the equation of the line is of the form:

y = - \frac {1} {3} x + b

We substitute one of the points and find b:

6 = - \frac {1} {3} (- 3) + b\\6 = 1 + b\\b = 5

Finally, the equation is:

y = - \frac {1} {3} x + 5

Answer:

y = - \frac {1} {3} x + 5

8 0
4 years ago
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