Evalute n/6 +2 when n = 12
2 answers:
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the correct question is
<span>The product of two consecutive even integers is 120. Find the integers
let
x-----------> first even integer
x+2-------> second consecutive even integer
we know that
x*(x+2)=120-------> x</span>²+2x-120=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=10
therefore
</span>first even integer is 10
second consecutive even integer is (10+2)----> 12
<span>
the answer is
10 and 12
</span>
<span>The product of two consecutive even integers is 120. Find the integers
let
x-----------> first even integer
x+2-------> second consecutive even integer
we know that
x*(x+2)=120-------> x</span>²+2x-120=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=10
therefore
</span>first even integer is 10
second consecutive even integer is (10+2)----> 12
<span>
the answer is
10 and 12
</span>