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2 years ago

12.642 to the nearest tenth

Mathematics

1 answer:

Evgen [1.6K]2 years ago

6 0

Answer:

12.6

Step-by-step explanation:

sorry only first one

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4. Two cylinders have dimensions in the ratio of 2:3. The smaller cylinder has a surface area of 16 cm.

Zarrin [17]

Answer:

(cross multiply)

2:3

16:X

2X=16×3

2x=48

x=48÷2

x=24

8 0

3 years ago

Hat is the value of the expression –5x4 when x = –2?

sleet_krkn [62]

$\bold{Hey\ there!}$

$\bold{Assuming,\ you\ meant: -5(-2)^4}$

$\bold{If\ so\ follow\ these\ steps\downarrow}$
$\bold{(-2)^4=16}$
$\bold{(-5)\times 16=-80}$
$\boxed{\boxed{\bold {Thus,\ your\ answer\ is: -80}}}\checkmark$

$\bold{Good\ luck\ on\ your\ assignment\ \& \ enjoy\ your\ day!}$

~ $\frak{LoveYourselfFirst:)}$

7 0

3 years ago

Simplify (-3x^2)^2 show work

Feliz [49]

Answer: 9x^4

Using the rules of exponents multiply the -3 times the -3 which equals 9 canceling out the negatives. Then you have that other ^2 but you also had the other one so you still have to keep it which equals that ^4.

6 0

3 years ago

Please answer the question correctly

miv72 [106K]

Answer:

Step-by-step explanation:

One property of a parallelogram is that diagonals bisect each other. This means that it "divides" each other in to two equal parts.

Since FK is 6, that means that KH is also 6.

Then you have to add both of those because FK and KH both make up the diagonal FH, FH is 12.

4 0

3 years ago

Read 2 more answers

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago